android无法获取文本并进行登录

Question

I am trying to create a login page to my Android App. I have 2 editview and a button. I am using a static user credentials to login. when I run the app, and try to login with the correct username and password, it gives incorrect credential message.

here is my code, it is a very simple piece of code

public void sendMessage(View view) {

    EditText user_name = (EditText)findViewById(R.id.txt_username);
    EditText password =(EditText)findViewById(R.id.txt_password);

    if(user_name.getText().toString()=="rotanet" && password.getText().toString()=="rotanet"){
        Intent intent = new Intent(this, MainActivity.class);
        startActivity(intent);
        TextView lbl_error = (TextView)findViewById(R.id.lbl_error);
        lbl_error.setText("");
    }
    else{
        TextView lbl_error = (TextView)findViewById(R.id.lbl_error);
        lbl_error.setText("wrong credentials!");
    }
}

Answer 1

You should use equals or equalsIgnoreCase instead of == to compare strings

Example:

 if(user_name.getText().toString().equals("rotanet") && password.getText().toString().equals("rotanet"))
{
stuff
}

Answer 2

You are using == to compare strings.

Use .equals insted.

if(user_name.getText().toString().equals("rotanet") && password.getText().toString().equals("rotanet")){

Answer 3

Use gettext().toString().equals("goodpass") instead of == when you check the password. == compares reference, not value.

Answer 4

Use .equals

if(user_name.getText().toString().equals("rotanet") && password.getText().toString().equals("rotanet"))
{
 //dosomething  
}

the == operator determines if 2 references point to the same object.

Answer 5

== is not used to compare contents of strings. Try user_name.getText().toString().equals("rotanet")

== tests for reference equality.

Answer 6

use equals method for comparison

if((user_name.getText().toString().equals("rotanet") && password.getText().toString().equals("rotanet"))
{

}