[英]Pick parts from a txt file and copy to another file with python
I'm in trouble here. 我在这里遇到麻烦了。 I need to read a file.
我需要读取一个文件。 Txt file that contains a sequence of records, check the records that I want to copy them to a new file.
包含一系列记录的Txt文件,检查我要将它们复制到新文件的记录。 The file content is like this (this is just an example, the original file has more than 30 000 lines):
文件内容是这样的(这只是一个示例,原始文件有3万多行):
AAAAA|12|120 #begin file
00000|46|150 #begin register
03000|TO|460
99999|35|436 #end register
00000|46|316 #begin register
03000|SP|467
99999|33|130 #end register
00000|46|778 #begin register
03000|TO|478
99999|33|457 #end register
ZZZZZ|15|111 #end file
The records that begin with 03000 and have the characters 'TO' must be written to a new file. 以03000开头且字符为“ TO”的记录必须写入新文件。 Based on the example, the file should look like this:
根据示例,文件应如下所示:
AAAAA|12|120 #begin file
00000|46|150 #begin register
03000|TO|460
99999|35|436 #end register
00000|46|778 #begin register
03000|TO|478
99999|33|457 #end register
ZZZZZ|15|111 #end file
Code: 码:
file = open("file.txt",'r')
newFile = open("newFile.txt","w")
content = file.read()
file.close()
# here I need to check if the record exists 03000 characters 'TO', if it exists, copy the recordset 00000-99999 for the new file.
I did multiple searches and found nothing to help me. 我进行了多次搜索,没有发现任何帮助。 Thank you!
谢谢!
with open("file.txt",'r') as inFile, open("newFile.txt","w") as outFile:
outFile.writelines(line for line in inFile
if line.startswith("03000") and "TO" in line)
If you need the previous and the next line, then you have to iterate inFile
in triads. 如果您需要上一行和下一行,那么您必须在三元组中迭代
inFile
。 First define: 首先定义:
def gen_triad(lines, prev=None):
after = current = next(lines)
for after in lines:
yield prev, current, after
prev, current = current, after
And then do like before: 然后像以前一样做:
outFile.writelines(''.join(triad) for triad in gen_triad(inFile)
if triad[1].startswith("03000") and "TO" in triad[1])
import re
pat = ('^00000\|\d+\|\d+.*\n'
'^03000\|TO\|\d+.*\n'
'^99999\|\d+\|\d+.*\n'
'|'
'^AAAAA\|\d+\|\d+.*\n'
'|'
'^ZZZZZ\|\d+\|\d+.*')
rag = re.compile(pat,re.MULTILINE)
with open('fifi.txt','r') as f,\
open('newfifi.txt','w') as g:
g.write(''.join(rag.findall(f.read())))
For files with additional lines between lines beginning with 00000, 03000 and 99999, I didn't find simpler code than this one: 对于以00000、03000和99999开头的行之间有其他行的文件,我发现没有比这更简单的代码了:
import re
pat = ('(^00000\|\d+\|\d+.*\n'
'(?:.*\n)+?'
'^99999\|\d+\|\d+.*\n)'
'|'
'(^AAAAA\|\d+\|\d+.*\n'
'|'
'^ZZZZZ\|\d+\|\d+.*)')
rag = re.compile(pat,re.MULTILINE)
pit = ('^00000\|.+?^03000\|TO\|\d+.+?^99999\|')
rig = re.compile(pit,re.DOTALL|re.MULTILINE)
def yi(text):
for g1,g2 in rag.findall(text):
if g2:
yield g2
elif rig.match(g1):
yield g1
with open('fifi.txt','r') as f,\
open('newfifi.txt','w') as g:
g.write(''.join(yi(f.read())))
file = open("file.txt",'r')
newFile = open("newFile.txt","w")
content = file.readlines()
file.close()
newFile.writelines(filter(lambda x:x.startswith("03000") and "TO" in x,content))
This seems to work. 这似乎有效。 The other answers seem to only be writing out records that contain '03000|TO|'
其他答案似乎只是写出包含“ 03000 | TO |”的记录 but you have to write out the record before and after that as well.
但您也必须在此前后写出记录。
import sys
# ---------------------------------------------------------------
# ---------------------------------------------------------------
# import file
file_name = sys.argv[1]
file_path = 'C:\\DATA_SAVE\\pick_parts\\' + file_name
file = open(file_path,"r")
# ---------------------------------------------------------------
# create output files
output_file_path = 'C:\\DATA_SAVE\\pick_parts\\' + file_name + '.out'
output_file = open(output_file_path,"w")
# create output files
# ---------------------------------------------------------------
# process file
temp = ''
temp_out = ''
good_write = False
bad_write = False
for line in file:
if line[:5] == 'AAAAA':
temp_out += line
elif line[:5] == 'ZZZZZ':
temp_out += line
elif good_write:
temp += line
temp_out += temp
temp = ''
good_write = False
elif bad_write:
bad_write = False
temp = ''
elif line[:5] == '03000':
if line[6:8] != 'TO':
temp = ''
bad_write = True
else:
good_write = True
temp += line
temp_out += temp
temp = ''
else:
temp += line
output_file.write(temp_out)
output_file.close()
file.close()
Output: 输出:
AAAAA|12|120 #begin file
00000|46|150 #begin register
03000|TO|460
99999|35|436 #end register
00000|46|778 #begin register
03000|TO|478
99999|33|457 #end register
ZZZZZ|15|111 #end file
Does it have to be python? 一定是python吗? These shell commands would do the same thing in a pinch.
这些shell命令在紧要关头会做同样的事情。
head -1 inputfile.txt > outputfile.txt
grep -C 1 "03000|TO" inputfile.txt >> outputfile.txt
tail -1 inputfile.txt >> outputfile.txt
# Whenever I have to parse text files I prefer to use regular expressions
# You can also customize the matching criteria if you want to
import re
what_is_being_searched = re.compile("^03000.*TO")
# don't use "file" as a variable name since it is (was?) a builtin
# function
with open("file.txt", "r") as source_file, open("newFile.txt", "w") as destination_file:
for this_line in source_file:
if what_is_being_searched.match(this_line):
destination_file.write(this_line)
and for those who prefer a more compact representation: 对于那些更喜欢紧凑的表示形式的人:
import re
with open("file.txt", "r") as source_file, open("newFile.txt", "w") as destination_file:
destination_file.writelines(this_line for this_line in source_file
if re.match("^03000.*TO", this_line))
code: 码:
fileName = '1'
fil = open(fileName,'r')
import string
##step 1: parse the file.
parsedFile = []
for i in fil:
##tuple1 = (1,2,3)
firstPipe = i.find('|')
secondPipe = i.find('|',firstPipe+1)
tuple1 = (i[:firstPipe],\
i[firstPipe+1:secondPipe],\
i[secondPipe+1:i.find('\n')])
parsedFile.append(tuple1)
fil.close()
##search criterias:
searchFirst = '03000'
searchString = 'TO' ##can be changed if and when required
##step 2: used the parsed contents to write the new file
filout = open('newFile','w')
stringToWrite = parsedFile[0][0] + '|' + parsedFile[0][1] + '|' + parsedFile[0][2] + '\n'
filout.write(stringToWrite) ##to write the first entry
for i in range(1,len(parsedFile)):
if parsedFile[i][1] == searchString and parsedFile[i][0] == searchFirst:
for j in range(-1,2,1):
stringToWrite = parsedFile[i+j][0] + '|' + parsedFile[i+j][1] + '|' + parsedFile[i+j][2] + '\n'
filout.write(stringToWrite)
stringToWrite = parsedFile[-1][0] + '|' + parsedFile[-1][1] + '|' + parsedFile[-1][2] + '\n'
filout.write(stringToWrite) ##to write the first entry
filout.close()
I know that this solution may be a bit long. 我知道这个解决方案可能会有点长。 But it is quite easy to understand.
但这很容易理解。 And it seems an intuitive way to do it.
这似乎是一种直观的方法。 And I have already checked this with the Data that you have provided and it works perfectly.
而且我已经使用您提供的数据进行了检查,它可以完美运行。
Please tell me if you need some more explanation on the code. 如果您需要有关代码的更多说明,请告诉我。 I will definitely add the same.
我一定会添加相同的内容。
I tip (Beasley and Joran elyase) very interesting, but it only allows to get the contents of the line 03000. I would like to get the contents of the lines 00000 to line 99999. I even managed to do here, but I am not satisfied, I wanted to make a more cleaner. 我给(Beasley和Joran elyase)小费很有趣,但它只允许获取03000行的内容。我想将00000行的内容获取到99999行。我什至设法在这里做,但我不是满意,我想做一个更清洁的。 See how I did:
看看我是怎么做的:
file = open(url,'r')
newFile = open("newFile.txt",'w')
lines = file.readlines()
file.close()
i = 0
lineTemp = []
for line in lines:
lineTemp.append(line)
if line[0:5] == '03000':
state = line[21:23]
if line[0:5] == '99999':
if state == 'TO':
newFile.writelines(lineTemp)
else:
linhaTemp = []
i = i+1
newFile.close()
Suggestions... Thanks to all! 建议...谢谢大家!
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