忽略带有正则表达式的URI段中的查询字符串？

Question

I have the following URI:

/host/segment1[?parm1=value1&param2=value2]/segment2/segment3[?parm1=value1&param2=value2]

As you can see I would like to ommit the content inside the square brackets just like if it were:

/host/segment1/segment2/segment3

EDIT:The square brackets are just examples of the content I want to ommit, they do not actully appear in the segments. A real examle would be:

/host/segment1?parm1=value1&param2=value2/segment2/segment3?parm1=value1&param2=value2

Is it possible to achieve this with a regular expression??

Answer 1

You do that with this:

$result = preg_replace('~\?[^/]++~', '', $uri);

Details:

\?       question mark
[^/]++  all characters that are not a slash one or more times

~        used to delimite the regular expression