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与excel VBA中的匹配功能不匹配

[英]Mismatch with match function in excel VBA

在此输入图像描述

I have the above data in row 1 (ie cell A1, cell B1, cell C1, etc). 我在第1行中有上述数据(即单元格A1,单元格B1,单元格C1等)。

I want to find the column number of the cell that contains Apr 2013. 我想找到包含2013年4月的单元格的列号。

Here's my code: 这是我的代码:

MsgBox Application.Match("Apr 2013", Range("1:1"), 1)

which returns mismatch error. 返回不匹配错误。 Any idea what went wrong? 知道出了什么问题吗?

You try this instead: 你试试这个:

Sub main()
    Dim stringToMatch$
    stringToMatch = "Apr 2013"
    Call DisplayMatchingColumnNumber(ActiveSheet, stringToMatch)
End Sub

Sub DisplayMatchingColumnNumber(ByRef ws As Worksheet, str$)
Dim i&, x$
    For i = 1 To ws.Cells(1, Columns.Count).End(xlToLeft).Column
        x = Right(CStr(ws.Cells(1, i).Value), 8)
        If StrComp(x, str, vbTextCompare) = 0 Then
            MsgBox "the column number is: " & i
        End If
    Next i
End Sub



As Microsoft says: 正如微软所说:

 Arg2 is Required of type Variant Lookup_array - a contiguous range of cells containing possible lookup values. Lookup_array must be an array or an array reference. 

Therefore: 因此:

 Sub ReadAboutFunctionsYouAreUsing() Dim x x = Array("Apr 2013", "Mar 2013", "Feb 2013") MsgBox Application.Match("Apr 2013", x, 1) End Sub 



User Defined Function 用户定义的功能
in any cell type: =getColumnNumber("Apr 2013") 在任何单元格类型中: =getColumnNumber("Apr 2013")

 Function getColumnNumber(str$) Dim i&, x$ For i = 1 To ActiveSheet.Cells(1, Columns.Count).End(xlToLeft).Column x = Right(CStr(ActiveSheet.Cells(1, i).Value), 8) If StrComp(x, str, vbTextCompare) = 0 Then getColumnNumber = i End If Next i End Function 

I get this sort of thing in VBA a lot, especially with dates. 我在VBA中经常遇到这种情况,尤其是日期。 Here's what I would do: 这就是我要做的事情:

Dim tmpRng As Range
Set tmpRng = ActiveWorkbook.Worksheets("Sheet1").Range("AA:650") 'or some other unused cell
tmpRng.Value = "Apr 2013"
MsgBox Application.Match(tmpRng, Range("1:1"), 1)
tmpRng.Value = ""

For some reason, Match seems to like having a cell reference as its first parameter. 出于某种原因,Match似乎喜欢将单元格引用作为其第一个参数。

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