在创建派生类Object时将参数传递给基类构造函数

Question

Consider two classes A and B

class A
{
public:
    A(int);
    ~A();
};

class B : public A
{
public:
    B(int);
    ~B();
};


int main()
{
    A* aobj;
    B* bobj = new bobj(5);    
}

Now the class B inherits A .

I want to create an object of B . I am aware that creating a derived class object, will also invoke the base class constructor , but that is the default constructor without any parameters.

What i want is that B to take a parameter (say 5), and pass it on to the constructor of A . Please show some code to demonstrate this concept.

Answer 1

Use base member initialisation:

class B : public A
{
public:
    B(int a) : A(a)
    {
    }
    ~B();
};

Answer 2

B::B(int x):A(x)
{
    //Body of B constructor
}

Answer 3

If you are using your derived class constructor just to pass arguments to base class then you can also do it in a shorter way in C++11:

class B : public A
{
    using A::A;
};

Note that I have not even used "public" access specifier before it. This is not required since inherited constructors are implicitly declared with same access level as in the base class.

For more details, please refer to section Inheriting constructors at: https://en.cppreference.com/w/cpp/language/using_declaration

Also you may refer to https://softwareengineering.stackexchange.com/a/307648 to understand limitations on constructor inheritance.

Answer 4

class A { public: int aval;

A(int a):aval(a){};
~A();

};

class B : public A { public: int bval;

B(int a,int b):bval(a),A(b){};
~B();

};

int main() {

  B *bobj = new bobj(5,6);
//or 
  A *aobj=new bobj(5,6); 

}

In this case you are assigning the values for base class and derived class .