如何使用PHP正确输出JSON数据

Question

I'm developing an Android app, and for the API I'm sending my requests to a URL that should return JSON data.

This is what I'm getting in my output:

And I'd like it to be displayed as Twitter response:

I'm assuming my response is not being parsed by the JSON Formatter Chrome extension because it's encoded badly, thus my app can't get the values I need.

Here's my PHP code:

<?php

$response = array();

if (isset($_POST['name']) && isset($_POST['price']) && isset($_POST['description'])) 
{

    $name = $_POST['name'];
    $price = $_POST['price'];
    $description = $_POST['decription'];

    require_once __DIR__ . '/db_connect.php';

    $db = new DB_CONNECT();

    $result = mysql_query("INSER INTO products(name, price, description) VALUES('$name', '$price', '$description')");

    if ($result) {
        $response["success"] = 1;
        $response["message"] = "Product successfully created.";

        echo json_encode($response);
    } else {

        $response["success"] = 0;
        $response["message"] = "Oops! An error occurred!";

        echo json_encode($response);
        }
} else {

    $response["success"] = 0;
    $response["message"] = "Required field(s) is missing";

    echo json_encode($response);

}

?>

I want to know how to display the JSON data correctly so that JSON Formatter and my android App can parse it correctly.

Answer 1

Your problem is actually very easy to solve. The Chrome JSON Formatter plugin only formats your output if the Content-Type header is set to application/json.

The only thing you need to change in your code is to use header('Content-Type: application/json'); in your PHP code, before returning the json-encoded data.

Answer 2

PHP's json_encode function takes a second argument, for $options . Here you can use JSON_PRETTY_PRINT to print it like you see in the Twitter API

Eg

echo json_encode($my_array, JSON_PRETTY_PRINT);

Answer 3

You can pass an argument to the json_encode function like this :

echo json_encode($response, JSON_PRETTY_PRINT);

PHP 5.2.0 => http://php.net/manual/en/function.json-encode.php

Answer 4

Your JSON should be like your first image; All in one line squished together. You can pass your output to jsonlint.com which can help you find your typo/bad data. ALL the current other answers could help you solve your issue as well. they all give you different options to format your output if you really want to do that.

Here's another way for you to display your JSON in HTML.

If you wrap your response in HTML < pre > tags you'll keep the white space format.

For example, I use jQuery to get some json data and in jQuery take the json object and put it directly in a < pre > that's formatted

<pre class="output" style="text-align:left; width:80%; margin:0 auto">[ results ]</pre>

I use

$('.output').html( JSON.stringify(data,null,4) );

This will take your json return, format it with spaces with the HTML < pre > can use to format it like you want to see.

If you want to have your json color coded... you can use http://prismjs.com/ or any other highlighting system...

Answer 5

Your JSON response is already in good shape. The reponse you are viewing is in Chrome browser. Thats why it looks like that . If you add below line in yoru code

var_dump($response); and then rightclick -> view source in chrome brower , you will see the tree structure. Anyway you can copy your JSON reponse and check the validy here

The same thing I belive first when I saw it in chrome . It happens to me also.

Answer 6

just Add pre Tag -->

<pre><?php  ---you`r code---     ?> </pre>

and

echo json_encode($response, JSON_PRETTY_PRINT);

after adding pre-Tag and JSON_PRETTY_PRINT I'm sure your Problem will solve.

Answer 7

Laravel

Setting header header('Content-Type: application/json'); or json PRETTY_PRINT didn't work?

A little bit of css is what you need white-space: pre-wrap;

You are dumping json to a blank page from controller or router?

Route::get('/print-json', function (Request $request) {
    echo '<style>body{ white-space: pre-wrap; }</style>';
    echo json_encode([
        'IP' => $request->getClientIp(),
        'Route' => $request->route(),
    ], JSON_PRETTY_PRINT);
});

Output:

{
    "IP": "127.0.0.1",
    "Route": {
        "uri": "showArray",
        "methods": [
            "GET",
            "HEAD"
        ],
        "action": {
            "middleware": "web",
            "uses": {},
            "namespace": "App\\Http\\Controllers",
            "prefix": null,
            "where": []
        },
        "isFallback": false,
        "controller": null,
        "defaults": [],
        "wheres": [],
        "parameters": [],
        "parameterNames": [],
        "computedMiddleware": [
            "web"
        ],
        "compiled": {}
    }
}

Answer 8

All you have to do is to add a second argument to the json_encode method like this.

echo json_encode($response_date, JSON_PRETTY_PRINT);

or

print json_encode($response_date, JSON_PRETTY_PRINT);

You can visit this link to read more on how to use json_encode .

Hope it helps.