[英]SqlAlchemy: How to use the result of a selected subquery inside the where clause
I wish to get a list of articles along with the count of the comments for each article我希望获得文章列表以及每篇文章的评论数
My query looks like this -我的查询看起来像这样 -
comments_subq = meta.Session.query(func.count(Comment.id)).filter(Comment.article_id==Article.id).as_scalar()
articles = meta.Session.query(Article, comments_subq.label("comment_count"))
articles = articles.filter(column('comment_count') >= 5)
it gives this error它给出了这个错误
column "comment_count" does not exist LINE 5: WHERE comment_count >= 5
How can I use the count which I selected to filter the result?如何使用我选择的计数来过滤结果?
Using the Query.subquery() method.使用Query.subquery()方法。
comments_subq = (
meta.Session.query(
Comment.article_id,
func.count(Comment.id).label("comment_count")
)
.group_by(Comment.article_id)
.subquery()
)
articles = (
meta.Session.query(
Article,
comments_subq.c.comment_count
)
.outerjoin(comments_subq, Article.id == comments_subq.c.article_id)
.filter(comments_subq.c.comment_count >= 5)
)
This works, but is it the most optimal query?这有效,但它是最佳查询吗?
count_subq = meta.Session.query(Comment.article_id, func.count(Comment.article_id) \
.label("comment_count")) \
.group_by(Comment.article_id) \
.subquery()
query = query.add_column(count_subq.c.comment_count.label("comment_count"))
query = query.outerjoin((count_subq, count_subq.c.article_id==Article.id))
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