MySQL的取数组忽略空值

Question

Here i am populating my dropdowns with database fields using php my code follows,

while ($row = mysql_fetch_array($result)) {
$series1 .= "<option id='Series1' value='" . $row['Series'] ."'>" . $row['Series'] ."             </option>";
}

after fetching i echo it to html

<select id="Series1"  onchange="changeVal('Series1')">
    <option value="">Please select</option>
        <?php echo $series1 ?>
</select>

my problem is i have some null values in the database field, i don't want that to be inserted in the options field. my final result now look like this

please help me.

Answer 1

Try this

while ($row = mysql_fetch_array($result)) {
   if($row['Series'] != '' || $row['Series'] != NULL) {
       $series1 .= "<option id='Series1' value='" . $row['Series'] ."'>" . $row['Series'] ."             </option>";
   }
}

OR

In your sql query

SELECT * FROM your_table WHERE Series IS NOT NULL

Answer 2

You can try like this

  while ($row = mysql_fetch_array($result)) {
  if(isset($row['Series'])) {
   $series1 .= "<option id='Series1' value='" . $row['Series'] ."'>" . $row['Series'] ."             </option>";
        }
      }

Answer 3

Try this...

<select id="Series1"  onchange="changeVal('Series1')">
    <option value="">Please select</option>


    <?php
while ($row = mysql_fetch_array($result)) 
{
    if($row['Series'] != '' || $row['Series'] != NULL) 
     {
?>
      <option value="<?php echo $row['Series']; ?>"><?php echo $row['Series']; ?></option>  
</select>



<?php
     }
}
?>