[英]Flourish: How to select one-to-many
Let's suppose there is a set of A and for each a of A there is a set of B. In short: A:B = 1:n 假设有一组A,并且每个A都有一组B。简而言之:A:B = 1:n
Let's suppose, there is an a, which is an A and it is interesting. 假设有一个,它是一个A,这很有趣。 However, I would like to select a with all its B elements.
但是,我想选择一个包含所有B元素的a。
For instance, let's consider the example of Companies and Workers. 例如,让我们考虑“公司和工人”的示例。 For the sake of simplicity, we assume that a Worker works at a single Company and a Company might have a natural number of Workers.
为简单起见,我们假设一个工人在单个公司工作,而一个公司可能有自然数量的工人。
If I want to select a set, containing the values of Company.Name, Worker.Name of a given Company, then what should I do in PHP, to achieve the expected result? 如果要选择一个包含给定公司的Company.Name,Worker.Name值的集合,那么我应该在PHP中做什么以达到预期的结果?
Based on your example, assuming you have this schema 根据您的示例,假设您具有此架构
Table Company 餐桌公司
Table Worker 餐桌工人
You can join the tables by linking Company
and Worker
with CompanyID
您可以通过将
Company
和Worker
与CompanyID
链接来加入表
SELECT a.Name CompanyName,
b.Name WorkerName
FROM Company a
INNER JOIN Worker b
ON a.CompanyID = b.CompanyID
To further gain more knowledge about joins, kindly visit the link below: 要进一步获得有关联接的知识,请访问以下链接:
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