连接两个表并从中获取值错误

Question

i am joining the two tables but is giving me error that mysql_fetch_array() expects parameter 1 to be resource,

<?php
$result=mysql_query("SELECT * FROM `photo_gallery`.`photographs` WHERE id=1");
$result .=mysql_query("SELECT * FROM `photo_gallery`.`users` WHERE id=1");
while($row=mysql_fetch_array($result))
{

echo 'You are Welcome'.'<br/>';
$Id=$row['id'];
$Name=$row['username'];
$Batch=$row['password'];
$Address=$row['first_name'];
$Course=$row['last_name'];
$filename=$row['filename'];
$type=$row['type'];
echo 'your ID is'.$Id.'<br/>'.'username '. $Name.'<br/>'.'your password '. $Batch.'<br/>'.'yor first name'. $Address. '<br/>'.'last'.$Course.'<br/>'.'file name is'.'<br/>'.$filename.'<br/>'.'type is '.$type;
}
?>

Answer 1

you cannot chain mysql queries in php that way. you have 2 options.

create a real mysql join.

you can use the shorthand syntax:

SELECT * FROM `photographs` p, `users` u WHERE p.id = u.id AND id=1

or a real join:

SELECT * FROM `photographs` p INNER JOIN `users` u WHERE p.id = u.id AND id=1

might i suggest reading more about mysql joins:

http://www.codinghorror.com/blog/2007/10/a-visual-explanation-of-sql-joins.html

Answer 2

Try this.

$query = "SELECT * FROM photographs INNER JOIN users ON photographs.id = users.id";
$result = mysql_query($query);

Answer 3

Here is the most easy syntax to use join function

$query=mysql_query("SELECT * FROM `databasename`.`firstablename` JOIN `seconddatabasename` ON firsttablename.id = secondtablename.id ");

If you want to work with join array than visit this link http://www.w3schools.com/php/func_string_join.asp . I hope you get what join function is used for.