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MySQL更新语句将无法执行

[英]Mysql update statement won't execute

Can somebody help me with this? 有人可以帮我吗? When i'm trying to update my table nothing happens and I can't figure out what's wrong. 当我尝试更新我的表时,什么也没有发生,而且我无法弄清楚出了什么问题。 I've tried different query's but not 1 worked. 我试过不同的查询,但没有1工作。

My code: http://pastebin.com/8zDpm0Ah it doesn't work from line 23 我的代码: http : //pastebin.com/8zDpm0Ah从第23行开始不起作用

<?php

foreach($db->query("SELECT * FROM blog WHERE ID LIKE '$ID'") as $row){

    echo "Titel: <input type='text' size='50' name='titel' value='$row[titel]'><br>";
    echo "Post:<br>";
    echo "<textarea name='editblog'>";
    echo $row[post];
    echo "</textarea>";

    echo "<input type='hidden' name='ID' value='";
    echo $row[ID];
    echo "'>";
}
?>

<input type="submit" value="Edit post" name="postedit">
</form>
<script>
CKEDITOR.replace( 'editblog' );
</script>
<?php

if(isset($_POST['postedit'])){
    $titel = $_POST['titel'];
    $post = $_POST['editblog'];
    $ID = $_POST['ID'];

    $STH = $db->prepare("UPDATE blog SET titel='$titel',post='$post' WHERE ID=$ID");  
    $STH->execute();
    echo "<h2>Post edited!</h2>";
}

If you aren't using prepared statements as they were intended (using $db->bind_params() ), then I recommend switching line 29 to 如果您没有按预期使用准备好的语句(使用$db->bind_params() ),则建议将第29行切换为

$STH = $db->query("UPDATE blog SET titel='$titel',post='$post' WHERE ID=$ID");  

and removing line 30. 并删除第30行。

You are not at all using parameterized queries, switching to PDO, does not mean only changing mysql_query() to $db->prepare() It is a little bit more than that. 您根本没有使用参数化查询,而是切换到PDO,这并不意味着仅将mysql_query()更改为$db->prepare()这还不止于此。 while using PDO, you can't place every variable in your query, I am talking about this code: 使用PDO时,您不能在查询中放置每个变量,我在谈论以下代码:

$STH = $db->prepare("UPDATE blog SET titel='$titel',post='$post' WHERE ID=$ID");  
                                $STH->execute();

The values, $title, $post and $id need to be replaced as ? 需要将值$title, $post and $id替换为? in your query, and later can be executed. 在您的查询中,以后可以执行。

So, try the following.: 因此,请尝试以下操作:

if(isset($_POST['postedit'])) {
     $title = $_POST['titel'];
     $post = $_POST['editblog'];
     $id = $_POST['ID'];
    try {
    $STH = $db->prepare("UPDATE blog SET titel = ?, post = ? WHERE ID = ? ");  
    $STH->execute(array($title, $post, $id));
    } catch(PDOExeption $e){
     echo 'The error is: '. $e->getMessage();
    }
    if($STH->rowCount() > 0){
       echo 'data updated successfuly';
    }else{
       echo 'data updating failed';
    }
}

Debugging: 调试:

    <?php
    $title = 'I am post title';
    $post = 'I am POST';
    $id = '17';

    try {
    new PDO("mysql:host=localhost;dbname=addictus_db", "addictus_admin", "dikketetten");
    $STH = $db->prepare("UPDATE blog SET titel = ?, post = ? WHERE ID = ? ");  
    $STH->execute(array($title, $post, $id));
    } catch(PDOExeption $e){
     echo 'The error is: '. $e->getMessage();
    } 

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