为什么在重载相等运算符时，您希望覆盖GetHashCode和Equals？

Question

Failing to override GetHashCode and Equals when overloading the equality operator causes the compiler to produce warnings. Why would it be a good idea to change the implementation of either? After reading Eric Lippert's blog post on GetHashCode it's seems like there probably aren't many useful alternatives to GetHashCode's base implementation, why does the compiler I encourage you to change it?

Answer 1

Let's suppose you are implementing a class.

If you are overloading == then you are producing a type that has value equality as opposed to reference equality.

Given that, now the question is "how desirable is it to have a class that implements reference equality in .Equals() and value equality in == ?" and the answer is "not very desirable". That seems like a potential source of confusion. (And in fact, the company that I now work for, Coverity, produces a defect discovery tool that checks to see if you are confusing value equality with reference equality for precisely this reason. Coincidentally I was just reading the spec for it when I saw your question!)

Moreover, if you are going to have a class that implements both value and reference equality, the usual way to do it is to override Equals and leave == alone, not the other way around.

Therefore, given that you have overloaded == , it is strongly suggested that you also override Equals .

If you are overriding Equals to produce value equality then you are required to override GetHashCode to match, as you know if you've read my article that you linked to.

Answer 2

If you don't override Equals() when you override == you will have some amazingly bad code.

How would you feel about this happening?

if (x == y)
{
   if (!x.Equals(y))
       throw new InvalidOperationException("Wut?");
}

---

Here's an example. Given this class:

class Test
{
    public int Value;
    public string Name;

    public static bool operator==(Test lhs, Test rhs)
    {
        if (ReferenceEquals(lhs, rhs))
            return true;

        if (ReferenceEquals(lhs, null) || ReferenceEquals(rhs, null))
            return false;

        return lhs.Value == rhs.Value;
    }

    public static bool operator!=(Test lhs, Test rhs)
    {
        return !(lhs == rhs);
    }
}

This code will behave oddly:

Test test1 = new Test { Value = 1, Name = "1" };
Test test2 = new Test { Value = 1, Name = "2" };

if (test1 == test2)
    Console.WriteLine("test1 == test2"); // This gets printed.
else
    Console.WriteLine("test1 != test2");

if (test1.Equals(test2))
    Console.WriteLine("test1.Equals(test2)");
else
    Console.WriteLine("NOT test1.Equals(test2)"); // This gets printed!

You do NOT want this!

Answer 3

My guess is that the compiler takes its clues from your actions, and decides that since you find it important to provide an alternative implementation of the equality operator, then you probably want the object equality to remain consistent with your new implementation of == . After all, you do not want the two equality comparisons to mean drastically different things, otherwise your program would be hard to understand even on a very basic level. Therefore, the compiler thinks that you should redefine Equals as well.

Once you provide an alternative implementation Equals , however, you need to modify GetHashCode to stay consistent with the equality implementation. Hence the compiler warns you that your implementation might be incomplete, and suggests overriding both Equals and GetHashCode .

Answer 4

If you don't overload the Equals method too, then using it might give different results from the ones you'd get with the operator. Like, if you overload = for integers...

int i = 1;
(1 == 1) == (i.Equals(1))

Could evaluate to false.

For the same reason, you should reimplement the GetHashCode method so you don't mess up with hashtables and such other structures that rely on hash comparisons.

Notice I'm saying "might" and "could", not "will". The warnings are there just as a reminder that unexpected things might happen if you don't follow its suggestions. Otherwise you'd get errors instead of warnings.

Answer 5

The documentation is pretty clear about this:

The GetHashCode method can be overridden by a derived type. Value types must override this method to provide a hash function that is appropriate for that type and to provide a useful distribution in a hash table. For uniqueness, the hash code must be based on the value of an instance field or property instead of a static field or property.

Objects used as a key in a Hashtable object must also override the GetHashCode method because those objects must generate their own hash code. If an object used as a key does not provide a useful implementation of GetHashCode, you can specify a hash code provider when the Hashtable object is constructed. Prior to the .NET Framework version 2.0, the hash code provider was based on the System.Collections.IHashCodeProvider interface. Starting with version 2.0, the hash code provider is based on the System.Collections.IEqualityComparer interface.