PHP找到匹配的eregi？

Question

I have this code here

$search = $_SERVER['HTTP_USER_AGENT'];

The Search returns Mozilla/5.0 (Android; Tablet; rv:14.0) Gecko/14.0 Firefox/14.0

This find is inside an array

$find = '(Nexus 7) | ((Android) && (Tablet))';

This if statement is inside a foreach statement hence the break.

if(eregi($find, $search)) {
    break;
}else{
    $os = "Unknown";
}

and my if statment returns Unknown!! is there something wrong with my find string ((Android) && (Tablet)) or is eregi not what I want to use?

Answer 1

This can be accomplished using strpos() and an if() test:

if ( false !== strpos( $search, 'Nexus 7' ) ||
     ( false !== strpos( $search, 'Android' ) && 
       false !== strpos( $search, 'Tablet' ) ) { ... }

Note that the 'value-and-type' test ( !== ) must be used here because strpos will return '0' if the search term is found at the beginning of the target string.

Answer 2

if (!preg_match("/Nexus 7|Andriod|Tablet/", $_SERVER['HTTP_USER_AGENT']) $os = "unknown";