PHP正则表达式删除非字母数字（句点除外）

Question

I'm having trouble finding a solution to this. How can I avoid losing the period in this regex?

$text = preg_replace('~[^\\pL\d]+~u', '-', $text);

Answer 1

$text = preg_replace('@[^0-9a-z\.]+@i', '-', $text);

以区分大小写的方式替换非0-9，az或句点的任何内容。

Answer 2

Just add the dot to your character class:

$text = preg_replace('~[^\\pL\d.]+~u', '-', $text);

You are using a negated character class (the [^ part) so anything that does not match any of the characters in that character class, gets replaced.

By the way, your question title does not match your regex.

Answer 3

What the heck is "\\\\pL"? AFAIK this matches a Backslash and the letters p and L.

Is this what you mean?

<?php 
echo preg_replace('/[^a-z0-9.]+/ui', '-', 'abc093.-23.-2ªıØẞÆ.23.OAIFJ→øæł¶iwoeweo');
?>

Result: abc093.-23.-2-.23.OAIFJ-iwoeweo

Answer 4

不要进行两次转义，并且要完全与Unicode兼容，数字是： \\pN然后：

$text = preg_replace('~[^\pL\pN]+~u', '-', $text);