[英]How to match a date pattern in strings
I am trying to match any number of correct format dates in a given string.我正在尝试匹配给定字符串中任意数量的正确格式日期。 For a date to be in correct format, it has to appear in the form dd-mm-yyyy.要使日期格式正确,它必须以 dd-mm-yyyy 形式出现。 Therefore dd and mm cannot have just one digit, they need 2 and they need to be in the correct range;因此 dd 和 mm 不能只有一位,它们需要 2 并且它们需要在正确的范围内; this means that day has to be between 1 and 31 and month has to be between 1 and 12.这意味着日期必须介于 1 和 31 之间,月份必须介于 1 和 12 之间。
I have it working for one type of input, but it does not match another input.我让它适用于一种类型的输入,但它与另一种输入不匹配。 Here is my code:这是我的代码:
#!/usr/bin/env python
from sys import stdin
from re import compile
myFormat = compile(r'(?=([0-2]\d|3[0-1])-(0\d|1[0-2])-(201[3-5]))' )
print myFormat.findall(stdin.readline())
Input 1:输入 1:
777-444---21-12-2013-12-2013-12-2013---444-777
Output:输出:
[('21', '12', '2013'), ('13', '12', '2013'), ('13', '12', '2013')]
So far so good.到现在为止还挺好。 But if I have the input:但如果我有输入:
0012-10-2012-10-2012
it matches nothing.它不匹配。 The correct output is supposed to be:正确的输出应该是:
[('12', '10', '2012'), ('12', '10', '2012')]
Please help me find the correct regex to do this请帮我找到正确的正则表达式来做到这一点
I only want to match only years 2012 to 2015.我只想匹配 2012 年到 2015 年。
If you change your regex to:如果您将正则表达式更改为:
myFormat = compile(r'(?=([0-2]\d|3[0-1])-(0\d|1[0-2])-(201[2-5]))' )
it will work (just change last [3-5]
to [2-5]
).它会起作用(只需将最后[3-5]
更改为[2-5]
)。 Currently it doesn't because you have:目前不是因为你有:
201[3-5]
for the year part, so it refuses to match 2012.对于年份部分,因此它拒绝匹配 2012 年。
For checking validity:检查有效性:
from sys import stdin
from re import compile
from datetime import datetime
myFormat = compile(r'(?=([0-2]\d|3[0-1])-(0\d|1[0-2])-(201[2-5]))' )
str1=("0012-10-2012-10-2012", "0031-02-2012");
for s in str1:
for date in myFormat.findall(s):
(d,m,y) = map(int, date)
try:
datetime(y,m,d)
print date
except: pass
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