将Ajax内容重定向到父页面
[英]Redirect ajax content to the parent page
问题描述
On a webpage I have some content loaded via Ajax. 
在网页上，我通过Ajax加载了一些内容。 If a user happens to visit the actual page that the ajax content is loaded from I want them to be redirected to the parent page itself. 如果用户碰巧访问了从中加载ajax内容的实际页面，我希望他们被重定向到父页面本身。 I thought I was being clever with the follow javascript, which works but seems dodgy and might break with a certain url: 我以为我对以下javascript很聪明，该javascript可以工作，但看起来有些晦涩，并且可能会破坏某些URL：
$url = top.location.href;
if($url.indexOf('/events/') <= 0){
window.location = site_url + "events/?event=" + id;
}
Is there a better way of doing this? 有更好的方法吗？ If this is possible in PHP this would be preferable. 如果这在PHP中是可能的，那将是可取的。
Thanks! 谢谢！
2 个解决方案
解决方案1
0 已采纳 2013-05-24 06:16:58
Please try this: 请尝试以下方法：
events.php events.php
<?php
if (empty($_SERVER['HTTP_X_REQUESTED_WITH']) || strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) != 'xmlhttprequest') {
header("Location: index.html");
exit;
}
echo "There are no events to display.";
?>
index.html index.html
<!DOCTYPE html>
<html>
<head>
<title>Events</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js" ></script>
</head>
<body>
<div class="test"></div>
<script>
$('.test').load('events.php');
</script>
</body>
</html>
A different approach might be like: 一种不同的方法可能是：
events.php events.php
<?php
if (!isset($_GET['a'])) {
header("Location: index.html");
exit;
}
echo "There are no events to display.";
?>
Then you can request with $('.test').load('events.php?a'); 然后，您可以请求$('.test').load('events.php?a'); . 。
Note that the user is always able to see the events no matter what you do, if the javascript can do it, they can too. 请注意，无论您做什么，用户始终可以看到事件，如果JavaScript可以做到，那么他们也可以看到。
解决方案2
0 2017-08-02 22:28:01
Try This: 尝试这个：
$.ajax({
type: "POST",
url: reqUrl,
data: reqBody,
dataType: "json",
success: function(data, textStatus) {
if (data.redirect) {
// data.redirect contains the string URL to redirect to
window.location.href = data.redirect;
}
else {
// data.form contains the HTML for the replacement form
$("#myform").replaceWith(data.form);
}
}
});
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