如何在现有的正则表达式中允许一组特殊字符？

Question

We have regex to validate password with one digit, one upper case letter and one lower case letter. Regex is:

^\w*(?=\w*\d)(?=\w*[a-z])(?=\w*[A-Z])\w*$

This regex will not allow any special characters. I need to change regex to allow some list of special characters and there should not be any restriction that there must be at least one special character. Only [-!$%^&*()_+|~=`{}\\[\\]:";'<>?,.\\/] should be allowed as special characters without must have one restriction.

I tried:

^\w*(?=\w*\d)(?=\w*[a-z])(?=\w*[A-Z])(?=\w*[-!$%^&*()_+|~=`{}\[\]:";'<>?,.\/]*)\w*$ 

and which seems to be wrong. Please some one help.

Answer 1

This is because of \\w* before $ .You are specifically trying to match 0 to many words..Try this:

^(?=.*\d)(?=.*[a-z])(?=.*[A-Z])[-\w!$%^&*()_+|~=`{}\[\]:";'<>?,.\/]+$

OR

^(?=.*\d)(?=.*[a-z])(?=.*[A-Z])[\w\p{Punct}]+$

\\p{Punct} is a special character class similar to [!"#$%&'()*+,\\-./:;<=>?@[\\\\\\]^_{|}~]