（js）仅用于匹配单词的正则表达式

Question

I'm making a dictionary application and need an regexp that check if the users input is only letters and spaces eventually. This is probably the most easiest regexp but i can figure it out. So far i have

/^[\w\D]$/ 

which is not working :/

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sorry guys, forgot to mention that will need to exclude all spec characters also.

Answer 1

You seem to want this one :

/^[\u00C0-\u1FFF\u2C00-\uD7FFa-zA-Z\s]+$/

It should accept only characters (including "not English" characters like the ones you have in Spanish and Cyrillic) as well as spaces, but exclude digits.

Example :

/^[\u00C0-\u1FFF\u2C00-\uD7FFa-zA-Z\s]+$/.test("переполнения стека")

returns true

Answer 2

Your regular expression matches exactly one such character.

You can add the + modifier to match one or more characters.

Answer 3

要匹配仅包含字母和空格字符的字符串，可以使用：

/^[a-zA-Z\s]+$/