从不是guid格式的字符串生成GUID

Question

I would like to generate a GUID from the input string. Let's say I have guid received from the user which is

81a130d2-502f-4cf1-a376-63edeb000e9f

so I can do:

 Guid g = Guid.Parse("81a130d2-502f-4cf1-a376-63edeb000e9f");

which is going to parse successfully.

But how to make user's life easier and allow to input:

81a130d2502f4cf1a37663edeb000e9f

which is without dashes, and still convert it to guid.

If I will try to use the same method it's gonna throw the exception complaining on the missing dashed in the guid format.

Any ideas?

Answer 1

尝试

Guid.ParseExact("81a130d2502f4cf1a37663edeb000e9f", "N");

Answer 2

The in addition to ParseExact (with "N" as the second argument), you could instead use the overload of the Guid constructor that accepts a string; it allows you to specify your value without dashes as well.

Guid g = new Guid("81a130d2502f4cf1a37663edeb000e9f");

Answer 3

使用ParseExact方法：

Guid.ParseExact("81a130d2502f4cf1a37663edeb000e9f","N")