bash脚本来拆分和反转文件名

Question

A bash script request(or fish script). I have a bunch of files like:

name - lastname.info
names  - lastnames.info
name & name - lastname & lastname.info

but I want to change all of them to:

lastname - name.info
lastnames - names.info
lastname & lastname - name & name - lastname & lastname.info

Answer 1

going by your sample data, you have " - " as the delimiter, so

for file in *; do
    ext=${file##*.}
    no_ext=${file%.*}
    name=${no_ext% - *}
    lastname=${no_ext##* - }
    mv "$file" "$lastname - $name.$ext"
done

For the gory details, see http://www.gnu.org/software/bash/manual/bashref.html#Shell-Parameter-Expansion

Answer 2

You could use a for loop to loop through all the files in the cwd, then use the cut utility to parse the file name based on the '-' delimiters to get first and last name (I then re-cut to parse out the file name extension), then use tr to remove the leading/trailing spaces. Finally concatenate, and you've got your new file name:

for file in *
do
    fname=`echo $file | cut -d '-' -f 1 | tr -d ' '`
    lname=`echo $file | cut -d '-' -f 2 | cut -d '.' -f 1 | tr -d ' '`
    newname=$lname' - '$fname.info
    echo $newname
done

Answer 3

Assuming all your files are in one directory:

for f in lastname*
do
    mv $f `echo $f | sed 's/lastname/name/'`
done

If your files are anywhere in the hierarchy, you will have to use the find command but the basic idea remains.