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使用较少的中间件将多个源CSS文件编译为一个?

[英]Using less-middleware to compile multiple source CSS files into one?

In my Node.js application, I am using less-middleware to compile the LESS files into CSS files. 在我的Node.js应用程序中,我正在使用较少中间件的软件将LESS文件编译为CSS文件。 Works great with single files: 适用于单个文件:

app.use(require('less-middleware')({ src: path.join(__dirname, '../', '/public/css') }));

However, I was wondering if it were possible to take two source .less files, and compile (and optinally minify) them into one single .css file. 但是,我想知道是否有可能获取两个源.less文件,并将它们编译(并最小化)为一个单独的.css文件。

Got it working using @import : 使用@import使其工作:

style.less style.less

... LESS code...

style2.less style2.less

... more LESS...

combined.less combined.less

@import "style";
@import "style2";

via Join two .less files into one css file 通过将两个.less文件合并为一个css文件

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