隐藏按钮Obj-C

Question

I'm looking to hide a button on my i-phone app and then by clicking another button it will appear. I've managed to make the button disappear with a click but can't figure out the opposite. I'm also new to Objective-C as you can probably tell so any tips on improving my code would be helpful. Thanks!

.h :

@property(nonatomic,retain) IBOutlet UIButton* button1 ;


-(IBAction)buttonTouch:(id)sender ;

.m :

@synthesize button1=_button1;

-(BOOL)hideOutlets {    
    _button1.hidden=TRUE;
}

-(void)buttonTouch:(id)sender {
    _button1.hidden =  !_button1.hidden;
}

Answer 1

Well to start from scratch, if you want to hide a button set its property hidden to YES, else if you want to make it reappear then set the property to NO.

Example:

button1.hidden=YES;
button1.hidden=NO;

Answer 2

Your code is basically correct

-(void)buttonTouch:(id)sender {
    _button1.hidden =  !_button1.hidden;
}

This code will hide your button when it's shown and show it when it's hidden. This should be correct.

You are saying

then by clicking another button it will appear

Are you sure both buttons have the touch-up-inside event properly connected to this action? I guess your problem will be that the buttonTouch: is not called when you touch the other button.

Answer 3

 @synthesize button1=_button1;
    -(BOOL)hideOutlets {

    _button1.hidden=TRUE;

}

-(void)buttonTouch:(id)sender {

        _button1.hidden = FALSE; //Or "NO" or "0", it's a boolean 
}

In addition, its weird setting a button hidden with a BOOL . If you want to have them hidden on load, go put _button1.hidden = YES; if you want it to hide it only when you have it visible, use

-(void)buttonTouch:(id)sender {
if(_button1.hidden == YES) 
    {
        _button1.hidden = NO; 
    }
else { _button1.hidden = YES; }
 }

Answer 4

I'll try to answer the question correctly as I understand it.

2 buttons, button1 and button2. Pressing button1 hides itself and shows button2. Pressing button2 hides itself and shows button1 again.

-(IBAction)button1Pressed:(id)sender {
    // button1 can only be pressed when not hidden, so we can dispense with checks for hidden
    [button1 setHidden:YES];
    [button2 setHidden:NO]; // assuming this button was hidden at startup
}

-(IBAction)button2Pressed:(id)sender {
    // button2 can only be pressed when not hidden, so no need to check for hidden
    [button2 setHidden:YES];
    [button1 setHidden:NO];
}

This should allow you to flip back and forth between buttons having them hide/show opposite of each other.

Answer 5

Two obvious problems with the code presented.

1) Cocoa uses YES and NO for boolean values not TRUE and FALSE.

2) You've declared a property, so you should use it in preference to the synthesised instance variable.

3) You're button touch method should return IBAction in the implementation as well as the interface.

Don't know if that'll fix your problem, but it's the first step to fix up your code.

@synthesize button1=_button1;

-(BOOL)hideOutlets {

    self.button1.hidden=YES;

}

-(IBAction)buttonTouch:(id)sender {

    self.button1.hidden =  !self.button1.hidden;
}