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过滤器IQueryable的动态表达式

[英]Dynamic expression for filter IQueryable

I have a situation where I have just the property name (string) and the value by which desire filter. 我遇到的情况是我只有属性名称(字符串)和所需过滤器的值。 I need to filter the list to return true if any name repeated. 如果需要重复任何名称,我需要过滤列表以返回true

Remembering that the filter should exclude it yourself. 记住过滤器应该自己排除它。 With expression like: p => p.Id != currentId 使用如下表达式: p => p.Id != currentId

Code

As the property is a string, I decided to create a Dynamic Expression to solve this problem. 由于该属性是字符串,因此我决定创建一个动态表达式来解决此问题。

[TestMethod]
public void TestingExpression()
{
    // Arrange
    var fix = new Fixture();
    var list = fix.Build<User>()
                    .With(p => p.Name)
                    .OmitAutoProperties()
                    .CreateMany(20).AsQueryable(); // Create IQueryable<User> with 20 users

    // Act 
    var currentId = 2;
    var uniquePropName = "Name";
    var uniqueValue = "{NotFoundValue}";

    // Expression: p => p.Id != currentId
    ParameterExpression pId = Expression.Parameter(typeof(int), "Id");
    ConstantExpression cId = Expression.Constant(currentId, typeof(int));
    BinaryExpression notCurrent = Expression.NotEqual(pId, cId);
    Expression<Func<int, bool>> NotCurrentExpr =
        Expression.Lambda<Func<int, bool>>(
            notCurrent,
            new ParameterExpression[] { pId });

    // Expression: p.{uniquePropName} == {uniqueValue}
    ParameterExpression pUnique = Expression.Parameter(typeof(string), uniquePropName);
    ConstantExpression cUnique = Expression.Constant(uniqueValue, typeof(string));
    BinaryExpression checkUnique = Expression.Equal(pUnique, cUnique);
    Expression<Func<string, bool>> CheckUniqueExp =
        Expression.Lambda<Func<string, bool>>(
            checkUnique,
            new ParameterExpression[] { pUnique });


    var exp = Expression.And(NotCurrentExpr, CheckUniqueExp);

    // Asset
    list.Provider.CreateQuery<User>(exp).ToList()
            .Should().HaveCount(19);

}

Question

The goal is to create a dynamic expression as: query.Any(p => p.Id != id && p.{Dynamic} == nome); 目标是创建一个动态表达式,如下所示: query.Any(p => p.Id != id && p.{Dynamic} == nome);

But I do not know how to continue .. 但是我不知道如何继续..

Thanks 谢谢

A nice tutorial can be found here . 一个很好的教程可以在这里找到。

You seem to be confusing the parameters and properties. 您似乎在混淆参数和属性。 Here is a further example: 这是另一个示例:

//user => user.SomeProperty == someValue

//the parameter of the predicate, a User object in your case 
ParameterExpression parameter = Expression.Parameter(typeof(User), "user");

//the property of the user object to use in expression
Expression property = Expression.Property(parameter, myPropertyNameString);

//the value to compare to the user property
Expression val = Expression.Constant(myValueToCompare);

//the binary expression using the above expressions
BinaryExpression expEquals = Expression.Equal(property, val);

//create the Expression<Func<T, Boolean>>
var predicate = Expression.Lambda<Func<User, Boolean>>(expEquals, parameter);

Furthermore in your code you try and create two lambdas whereas your aim is to produce 此外,在您的代码中,您尝试创建两个lambda,而您的目标是生成

p => p.Id != id && p.{Dynamic} == nome

This is a single lambda that takes 1 parameter with the body consisting of two binary expressions and a conditional AND operator producing a Boolean result. 这是一个带1个参数的lambda,其主体由两个二进制表达式和一个条件AND运算符组成,该运算符产生Boolean结果。 You should instead use Expression.AndAlso() to apply the && operator to your binary expressions and then use Expression.Lambda<Func<User, Boolean>>() to get your final lambda expression. 您应该改为使用Expression.AndAlso()&&运算符应用于二进制表达式,然后使用Expression.Lambda<Func<User, Boolean>>()获得最终的lambda表达式。

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