为什么我的功能无法打印

Question

So I have this function.

def test(fourBits):
  binaryDigits = fourBits
  if binaryDigits[1] == 1:
     print 'test'

If I enter test('1111') it won't print test . I don't understand why it is not?

Answer 1

binaryDigits [1]是字符串，1是整数

Answer 2

Use this:

if int(binaryDigits[1]) == 1:

or this:

if binaryDigits[1] == '1':

so that the types match, ie, compare two characters or two numbers.

Answer 3

Perhaps what you want is something like this. Use integer instead of string, and test the bit by bitwise operators.

def test(value):
    if (value >> 1) & 1:
        print 'true'

Here is the result.

>>> test(0b0010)
true
>>> test(0b0000)
>>>

Answer 4

尝试print binaryDigits[1]之前，您if语句来看看什么是由你的隐藏if语句。