[英]shell script for subversion files
The script is not working for "?" 该脚本不适用于“?” case.
案件。 When i run in command line directly ...works okay but in script is not able to run the "?"
当我直接在命令行中运行时...可以,但是在脚本中无法运行“?” condition.
条件。
svn st svn_promote_WP
M svn_promote_WP\Code\Environment\DEV\properties\build.properties
M svn_promote_WP\Code\Environment\RT\properties\build.properties
? svn_promote_WP\props.pl
this is my script: 这是我的脚本:
#!/usr/bin/sh
meta_data=(`svn st svn_promote_WP | cut -c1`)
meta_files=(`svn st svn_promote_WP | awk '$1~/^[AMD?]$/{for(i=2;i<=NF;i++)print $i}'`)
for index in ${!meta_data[*]}
do
if [ ${meta_data[$index]} = "?" ]; then
echo "${meta_files[$index]} need to be added"
elif [ ${meta_data[$index]} = "M" ]; then
echo "${meta_files[$index]} are modified"
fi
done
Output: 输出:
svn_promote_WP\Code\Environment\DEV\properties\build.properties are modified
svn_promote_WP\Code\Environment\RT\properties\build.properties are modified
Desired output: 所需的输出:
svn_promote_WP\Code\Environment\DEV\properties\build.properties are modified
svn_promote_WP\Code\Environment\RT\properties\build.properties are modified
svn_promote_WP\props.pl need to be added
Updated more details - results when run on command line: 更新了更多详细信息-在命令行上运行时的结果:
$ svn st svn_promote_WP | cut -c1
M
M
?
$ svn st svn_promote_WP | awk '$1~/^[AMD?]$/{for(i=2;i<=NF;i++)print $i}'
svn_promote_WP\Code\Environment\DEV\properties\build.properties
svn_promote_WP\Code\Environment\RT\properties\build.properties
svn_promote_WP\props.pl
It's a quoting problem, but a non-trivial one. 这是一个报价问题,但不是一个简单的问题。 First, you didn't enclose
${meta_data[$index]}
in double quotes in the tests. 首先,您没有在测试
${meta_data[$index]}
括在双引号中。 And second, the ?
二是
?
was already expanded in the array assignment. 已在数组分配中扩展。 Unfortunately, this second problem cannot be fixed by adding double quotes;
不幸的是,第二个问题无法通过添加双引号解决。 you need something more tricky, namely
您需要更棘手的东西,即
set -f
meta_data=(`svn st svn_promote_WP | cut -c1`)
meta_files=(`svn st svn_promote_WP | awk '$1~/^[AMD?]$/{for(i=2;i<=NF;i++)print $i}'`)
set +f
What's the reason? 什么原因? In your original code, bash performs two operations on the output of
svn st svn_promote_WP | cut -c1
在您的原始代码中,bash在
svn st svn_promote_WP | cut -c1
的输出上执行两项操作svn st svn_promote_WP | cut -c1
svn st svn_promote_WP | cut -c1
: It splits it into individual words whenever it encounters whitespace, and it expands globbing characters (= filename expansion). svn st svn_promote_WP | cut -c1
:每当遇到空格时,它将其拆分为单个单词,并扩展通配符(=文件名扩展)。 So, if you have a file z
in the current directory, ?
因此,如果当前目录中有文件
z
,则?
is replaced by z
. 被
z
替换。 Double quotes around `svn st svn_promote_WP | cut -c1`
`svn st svn_promote_WP | cut -c1`
周围的双引号`svn st svn_promote_WP | cut -c1`
`svn st svn_promote_WP | cut -c1`
would prevent both word splitting and filename expansion, so that the entire output of svn st svn_promote_WP | cut -c1
`svn st svn_promote_WP | cut -c1`
可以防止字分割和文件名扩展,因此svn st svn_promote_WP | cut -c1
的整个输出svn st svn_promote_WP | cut -c1
svn st svn_promote_WP | cut -c1
is assigned unmodified to the first array element. svn st svn_promote_WP | cut -c1
未修改地分配给第一个数组元素。 But you need something different, namely "keep word splitting, but prevent filename expansion". 但是您需要一些不同的东西,即“保留单词拆分,但防止文件名扩展”。 In order to get that effect, you must omit the double quotes and use a shell option that disables filename expansion, namely
-f
. 为了获得这种效果,您必须省略双引号,并使用一个禁用文件名扩展的shell选项,即
-f
。 After the assignment is done, you can restore the normal shell behavior by executing set +f
. 分配完成后,您可以通过执行
set +f
恢复正常的shell行为。
Quote the usage of your variables: 引用变量的用法:
if [ "${meta_data[$index]}" = "?" ]; then
echo "${meta_files[$index]} need to be added"
elif [ "${meta_data[$index]}" = "M" ]; then
echo "${meta_files[$index]} are modified"
fi
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