如何在R中将矩阵转换为数据帧

Question

I have a matrix like this:

x

  [,1]   [,2]  
[1,] List,5 List,5
[2,] List,5 List,5
[3,] List,5 List,5
[4,] List,5 List,5
[5,] List,5 List,5
[6,] List,5 List,5

How would I convert this to a data frame?

when I do this:

head(x[1,1],2)
[[1]]

               DATE_TIME                                                     SITE RESPONSE_TIME AVAIL_PERCENT AGENT
1   2013-MAY-24 05:09 PM  Keynote Business 40 TxP - User Time (seconds)[Geo Mean]             -             - 45693
2   2013-MAY-24 05:24 PM  Keynote Business 40 TxP - User Time (seconds)[Geo Mean]             -             - 45693
3   2013-MAY-24 05:39 PM  Keynote Business 40 TxP - User Time (seconds)[Geo Mean]             -             - 45693
4   2013-MAY-24 05:54 PM  Keynote Business 40 TxP - User Time (seconds)[Geo Mean]             -             - 45693
5   2013-MAY-24 06:09 PM  Keynote Business 40 TxP - User Time (seconds)[Geo Mean]             -             - 45693

Answer 1

The first thing to address is whether the location in that matrix of lists has any meaning. If you only want to "flatten" it out", you could just do this:

 # Not workig : out <- do.call( as.data.frame, c(x) )
 # Then try:

out <- do.call( rbind, as.list(x) )

If you want a record of the locations you will need to use an approach that labels the output, perhaps with apply or by processing one matrix column at a time.