[英]Transform zip directory function using java.util.zip to use LZMA
I currently have a function makeBackup() which zips an entire directory into a zip file, the files are however too big so we decided to switch to LZMA. 我目前有一个函数makeBackup(),它将整个目录压缩为一个zip文件,但是文件太大,因此我们决定切换到LZMA。 We found a library which does this ( lzma-java ) however it seems to compress only a single file, while the zip function we used permits to add files and directories to a zip file.
我们找到了一个执行此操作的库( lzma-java ),但是它似乎仅压缩单个文件,而我们使用的zip函数允许将文件和目录添加到zip文件中。
How can we implement the same with LZMA by changing our function? 如何通过更改功能用LZMA实现相同的功能? I added our current function below:
我在下面添加了当前功能:
private static void makeBackup()
{
String backupPathString = "/home/backups";
/* zip remote file */
try
{
//name of zip file to create
String zipFilename = "backup.zip";
//create ZipOutputStream object
ZipOutputStream zipOutStream = new ZipOutputStream(new FileOutputStream(zipFilename));
//path to the currentFile to be zipped
File zipFolder = new File(backupPathString);
//get path prefix so that the zip file does not contain the whole path
// eg. if currentFile to be zipped is /home/lalit/test
// the zip file when opened will have test currentFile and not home/lalit/test currentFile
int len = zipFolder.getAbsolutePath().lastIndexOf(File.separator);
String baseName = zipFolder.getAbsolutePath().substring(0, len + 1) + File.separator + "todaybackups";
zipFilesInPath(zipOutStream, backupPathString, baseName);
zipOutStream.flush();
zipOutStream.close();
}
catch (IOException e)
{
}
}
private static void zipFilesInPath(ZipOutputStream zipOutputStream, String filePath, String baseName) throws IOException
{
File currentFile = new File(filePath);
ArrayList<File> filesArrayList = new ArrayList<File>(Arrays.asList(currentFile.listFiles()));
if (filesArrayList.isEmpty())
{
String name = currentFile.getAbsolutePath().substring(baseName.length());
ZipEntry zipEntry = new ZipEntry(name + "/" + ".");
zipOutputStream.putNextEntry(zipEntry);
}
for (File file : filesArrayList)
{
if (file.isDirectory())
{
zipFilesInPath(zipOutputStream, file.getAbsolutePath(), baseName);
}
else
{
String name = file.getAbsolutePath().substring(baseName.length());
ZipEntry zipEntry = new ZipEntry(name);
zipOutputStream.putNextEntry(zipEntry);
IOUtils.copy(new FileInputStream(file), zipOutputStream);
zipOutputStream.closeEntry();
}
}
}
private static void unzipFilesToPath(ZipInputStream zipInputStream, String fileExtractPath) throws IOException
{
ZipEntry entry;
while ((entry = zipInputStream.getNextEntry()) != null)
{
int count;
byte[] data = new byte[2048];
/*let's make the directory structure needed*/
File destFile = new File(fileExtractPath, entry.getName());
File destinationParent = destFile.getParentFile();
// create the parent directory structure if needed
destinationParent.mkdirs();
if (!entry.isDirectory() && !entry.getName().substring(entry.getName().length() - 1).equals("."))
{
final FileOutputStream fos = new FileOutputStream(fileExtractPath + File.separator + entry.getName());
final BufferedOutputStream dest = new BufferedOutputStream(fos, 2048);
while ((count = zipInputStream.read(data, 0, 2048)) != -1)
{
dest.write(data, 0, count);
}
dest.flush();
dest.close();
}
}
}
apparently is not possible, and what you have to do is package all your files into a tar/zip and then apply the lzma. 显然是不可能的,您要做的是将所有文件打包到tar / zip中,然后应用lzma。 take a look at this How to use LZMA SDK to compress/decompress in Java
看看这个如何在Java中使用LZMA SDK进行压缩/解压缩
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