SQl查询以从单行作为多行获取数据

Question

Can someone help me with this.

I have a table structure as follows

Department_name | Owner_ID | Approver_ID
-----------------------------------------
Dept 1          | 1234567  | 1234567

Now I want the output based on the employee ID as follows

like

select department_name,Role  where Owner_ID= '1234567' or Approver_ID = '1234567'

Department_name | Role
------------------------- 
Dept 1          | Owner
Dept 1          | Approver

More importantly, I need to get it as two separate rows as shown above and Role is not a column in the table its value wil be either Approver or Owner based on given ID.

I am unable to figure out how to get this. Thanks in advance.

Answer 1

A simple solution would be a union: http://sqlfiddle.com/#!6/f13c9/5/0

SELECT
  Department_name,
  'Owner'
FROM test
WHERE Owner_ID = 1234567

UNION ALL

SELECT
  Department_name,
  'Approver'
FROM test
WHERE Approver_ID = 1234567

Answer 2

Please Try This..

SELECT Department_name,
CASE WHEN Role = (SELECT Owner_ID FROM Department) 
THEN 'Owner' ELSE 'Approver'
END AS Role
FROM Department
UNPIVOT(Role for Column1 in(Owner_ID,Approver_ID)) AS Role

Answer 3

Also you can use APPLY operator

SELECT t.Department_name, o.Role       
FROM dbo.YourTable t 
  CROSS APPLY (
               VALUES(CASE WHEN t.Owner_ID = '1234567' THEN 'Owner' END),
                     (CASE WHEN t.Approver_ID = '1234567' THEN 'Approver' END)
               ) o(Role)
WHERE o.Role IS NOT NULL

Answer 4

try out this

SELECT Department_name , Role FROM TableName UNPIVOT (Role for Department_name in (Owner_ID , Approver_ID)) AS Role