awk函数不允许返回

Question

i have functions in my awk script to parse lines contains certain words/characters

function tohyphen (o) {
        split ($0,a,"to[-_]")
        split (a[2],b,"-")
        k=b[1]
        p=b[2]
        return k
}

function tospace (o) {
        split ($0,a,"to ")
        split (a[2],b,"-")
        k=b[1]
        p=b[2]
        return k
}

funtion pipe (o) {
        split ($0,a,"|")
        split (a[2],b,"-")
        x=b[1]
        y=b[2]
        return x
        #return x
}
{
#if (match ($0, /to[-_]/))
if ($0 ~ /to[-_]/)
        print "found to- for interface ", $1, " is ", tohyphen($0), "is ",p, " is ", $1="",$0

else if ($0 ~ /to /)
        #(match ($0, /to /))
        print "found to  for interface", $1, " is ", tospace($0), "  is ", p, " is ", $1="",$0
else if ($0 ~ /\|/)
#       pipe($0)
        print "found to  for interface", $1, " is ",topipe($0), "  is ", y, " is ", $1="",$0
else
        print $1, $1="",$0
}

in the third function which just searches for a match to pipe it does not allow me return anything, giving me the error return is outside of function. any idea what could be the problem or any other way for me to run this.

Answer 1

Try spelling function correctly! You have funtion not function. Are you using an editor with syntax highlighting for awk ? You can see from stackoverflows markup that funtion is not a reserved word.