链接到C＃中的控制面板（运行播发的程序和Configuration Manager）

Question

I am trying to link to the control panel from within a C# application. I am coding in visual studio and trying to find a way to make a link to those two areas in the control panel.

I have been using System.Diagnostics.Process.Start() but I can't seem to find a way to actually link my way to anywhere inside of the control panel except for a select few places where applets are already defined, such as printers and color.

Please let me know if you have any idea how to come upon this solution.

Answer 1

this works for me:

var cplPath = System.IO.Path.Combine(Environment.SystemDirectory, "control.exe");
System.Diagnostics.Process.Start(cplPath, "/name Microsoft.ProgramsAndFeatures");

You can also specify a page of the control panelitem. Check out Executing Control Panel Items and Canonical Names of Control Panel Items

Answer 2

If you just want to launch a control panel window the command is

System.Diagnostics.Process.Start("control");

If you want to launch the individual items in the control panel, you need to know it's filename (check the Windows\\System32 or Windows\\SYSWOW64 for the files, they end in .cpl ) you can then launch it like this.

System.Diagnostics.Process.Start("control", "powercfg.cpl");

Answer 3

If you type "Start Control" or "Control" into Command Prompt it will open Control Panel.

Therefore I would run a Process and run it. This Code (Bellow) worked perfectly for me:

public Form1()
{
     InitializeComponent();
}

    #region Variables
    Process p;
    #endregion Variables

    [...]

    void myMethod()
    {
            try
            {
                p = new Process();
                p.StartInfo.FileName = "cmd.exe";
                p.StartInfo.RedirectStandardInput = true;
                p.StartInfo.RedirectStandardOutput = true;
                p.StartInfo.CreateNoWindow = true;
                p.StartInfo.UseShellExecute = false;
                p.Start();

                p.StandardInput.WriteLine("start control"); 
                p.StandardInput.Flush();
                p.StandardInput.Close();
                Console.WriteLine(p.StandardOutput.ReadToEnd());
            }
            catch (Exception ex) { MessageBox.Show(ex.Message); }
    }