[英]How do I copy the contents of a bytearray to a list (Python)?
I have a dictionary which I convert to a bytearray, and since bytearrays are immutable (can't be modified) I try to make a list equal to each index in the bytearray. 我有一个字典,我转换为bytearray,因为bytearrays是不可变的(无法修改)我尝试使列表等于bytearray中的每个索引。
a = {1:'a', 2:'b', 3:'c'}
b = bytearray(str(a), 'ASCII')
c = []
for i in b:
c[i] = b[i] # Error on this line
print(str(c))
The problem is it keeps printing IndexError: bytearray index out of range
. 问题是它不断打印IndexError: bytearray index out of range
。
How and why is the bytearray out of range? bytearray如何以及为何超出范围?
If I correctly understood your question, you can simply use c = list(b)
: 如果我正确理解了你的问题,你可以简单地使用c = list(b)
:
a = {1:'a', 2:'b', 3:'c'}
b = bytearray(str(a), 'ASCII')
c = list(b)
print(c)
Output: 输出:
[123, 49, 58, 32, 39, 97, 39, 44,
32, 50, 58, 32, 39, 98, 39, 44,
32, 51, 58, 32, 39, 99, 39, 125]
In order to understand why you get this error, see this answer . 为了理解您收到此错误的原因,请参阅此答案 。
i
is the value in b
not the index i
是b
的值而不是索引
b = [1,5,20]
for i in b:
print i #prints 1,then 5 , then 20
To fix your code: 要修复您的代码:
a = {1:'a', 2:'b', 3:'c'}
b = bytearray(str(a), 'ASCII')
c = []
for i in b:
c.append(i)
or, better still, you can use the byte array directly with the list
constructor and forgo the loop: 或者,更好的是,您可以直接使用字节数组与list
构造函数并放弃循环:
c=list(b)
or, skip the byte array and use a list comprehension: 或者,跳过字节数组并使用列表解析:
c= [ord(ch) for ch in str(a)]
In all these cases, you get the list of ASCII ordinals if that is your goal: 在所有这些情况下,如果这是您的目标,您将获得ASCII序列列表:
[123, 49, 58, 32, 39, 97, 39, 44, 32, 50, 58, 32, 39, 98, 39, 44, 32, 51, 58, 32, 39, 99, 39, 125]
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