[英]using playframework how to list values
get an error 得到一个错误
Cannot use a method returning Unit as an Handler 无法使用将Unit返回为Handler的方法
inside Application 内部应用
def listAllFriends(userId:Long){
val myfriend:List[MyFriend]=MyFriend.listAllFriendByUser(userId)
Ok(views.html.allFriends.render(myfriend))
}
in views page 在视图页面
@(myFriends: List[MyFriend])
@for(myFriend <- myFriends){
@myFriend.friend_Id <br>
}
In routes 在路线上
GET /allFriend controllers.Application.listAllFriends(postId:Long)
And in model 并在模型中
model have myfriend got 4 values id,userId,friendId and isAccept. 模型让myfriend获得4个值id,userId,friendId和isAccept。 userId and FriendId are the ForeignKey from table UserProfile.. userId和FriendId是表UserProfile中的ForeignKey。
def listAllFriendByUser(user_Id:Long):List[MyFriend]={
DB.withConnection { implicit connection =>
val friendByUser= SQL(
"""
select * from MY_FRIEND where USER_ID ={user_Id}
""").on(
'user_Id -> user_Id).as(MyFriend.simple.*)
friendByUser
}
}
In routes, try : 在路线上,请尝试:
POST /allFriends controllers.Application.listAllFriends(userId:Long)
See Play 2.0 framework - POST parameters 请参阅Play 2.0框架-POST参数
And in Application, you have missed the 'Action' : 在Application中,您错过了“ Action”:
def listAllFriends(userId:Long) = Action {...}
In your routes file you call the method listAllFriends() without argument, while it is defined as def listAllFriends(userId:Long). 在路由文件中,您将不带参数的方法调用listAllFriends(),而将其定义为def listAllFriends(userId:Long)。 You must pass it the userId parameter... 您必须向其传递userId参数...
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