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移动子视图时，如何在其超视图中将其子视图保留在同一位置？

[英]When moving a subview around, how do I keep a subview of it in the same place in its superview?

原文 2013-05-31 16:06:19 7 2 ios/ objective-c/ uiview/ uiimageview/ uigesturerecognizer

That's a very convoluted title. 这是一个非常令人费解的标题。 Sorry. 抱歉。

Basically, I have a UIView that I've attached to a UITableViewCell so I can slide the cell around, or at least create the tric-- illusion of it. 基本上，我有一个UIView ，我已经附加到UITableViewCell所以我可以滑动单元格，或至少创建它的幻觉 - 幻觉。 Within that UIView I have a UIImageView . 在UIView我有一个UIImageView 。 I want to keep this UIImageView static relative to the view controller . 我想保持这个UIImageView相对于视图控制器静态。 So basically when I slide the cell around, I want everything about the cell to slide around with my finger (I have this done) EXCEPT the UIImageView . 所以基本上当我滑动单元格时，我希望用手指滑动单元格的所有内容（我已完成）除了UIImageView 。 I want it to seem to the user like it's staying in one place -- which means to the cell's superview (the view controller's view) it's staying in one place. 我希望用户觉得它似乎停留在一个地方 - 这意味着单元格的超级视图（视图控制器的视图）它停留在一个地方。

What would be the easiest way to build this? 构建这个最简单的方法是什么？ I'm sorry I don't have code to share, I'm just trying to build this from a conceptual level first. 对不起，我没有代码要分享，我只想先从概念层面构建这个代码。 My UIView on the UITableViewCell is slid with a UIPanGestureRecognizer and moving the UIView 's frame if that helps. 我在UITableViewCell上的UIView滑动了一个UIPanGestureRecognizer并移动了UIView的帧，如果这有帮助的话。

Would I have to move it in the opposite direction of the UIView when it moves (say it moves one forward in x, move it one back in x?) or is there a way where I can just say "lock your position relative to your super-superview"? 当UIView移动时，我是否必须将它向UIView的相反方向移动（比如它在x中向前移动一个，在x中向后移动一个？）或者有一种方法可以说“锁定相对于你的位置”超上海华“？

2 个解决方案

I've had the same problem before.. what I did was simply not add the UIImageView as a subview to the UITableViewCell , and instead attach it to the parent of the UITableViewCell .. that way whatever happens to the UITableViewCell frame properties (ie size or origin) won't impact your UIImageView .. 我之前遇到过同样的问题..我所做的只是不将UIImageView作为子视图添加到UITableViewCell ，而是将其附加到UITableViewCell的父级..这样就可以了解UITableViewCell框架属性（即大小）或来源）不会影响你的UIImageView ..

you may wonder: well one of the reasons I attach the UIImageView as a subview to the tableCell is b/c it's related to it in many different ways.. The response to that is that you can associate an object with another through objc_setAssociatedObject 您可能想知道：我将UIImageView作为子视图附加到tableCell的原因之一是b / c它以多种不同的方式与它相关。对此的响应是您可以通过objc_setAssociatedObject将对象与另一个对象关联

If you come from web dev background, you can think of this discussion as the difference between position:absolute and position:relative discussion. 如果您来自web dev背景，您可以将此讨论视为position:absolute和position:relative之间的区别position:relative讨论。

Initially I tried to do what you had in mind, basically moving them in opposite directions etc.. I just think my solution is a lot simpler to do. 最初我试图做你想到的事情，基本上是朝着相反的方向移动它们。我只是认为我的解决方案要简单得多。

abood was close, but close, but if you simply make the imageview a subview of the cell itself instead of the UIView I added over the cell, they operate independently. abood很接近，但接近，但是如果你只是让imageview成为单元格本身的子视图而不是我在单元格上添加的UIView，它们就会独立运行。 So contrary to the first line, adding it as a subview of UITableViewCell worked perfectly and didn't have any of the issues outlined. 因此，与第一行相反，将其添加为UITableViewCell的子视图非常有效，并且没有列出任何问题。 Works perfectly now. 现在工作得很好。