Laravel形式模型绑定

Question

I've been reading about this feature: http://laravel.com/docs/html#form-model-binding 我一直在阅读这个功能： http ： //laravel.com/docs/html#form-model-binding

And it looks really neat, but there are couple of things that I'm not certain about. 它看起来很整洁，但有几件我不确定的事情。

Do I need to put any code in the controller action to process this form? 我是否需要在控制器操作中放置任何代码来处理此表单？ What does that look like? 那是什么样的？

The model (User) I want to bind in my form has a separate table for addresses. 我想在我的表单中绑定的模型（用户）有一个单独的地址表。 So I want to be able to fill out the User model's fields, but also the fields for the related Address model. 所以我希望能够填写用户模型的字段，还能填写相关地址模型的字段。 Can I do that with form-model-binding, or do I have to handle the form manually? 我可以使用表单模型绑定来执行此操作，还是必须手动处理表单？

Or, failing that, can I use form model binding for the user fields, but manually handle the address fields? 或者，如果不这样做，我可以对用户字段使用表单模型绑定，但是手动处理地址字段吗？

Answer 1

You don't need any different code in your controller to process this form. 您的控制器中不需要任何不同的代码来处理此表单。 All your (named) form variables will be in Input::all(). 所有（命名）表单变量都将在Input :: all（）中。

The model ($user) you pass in 您传入的模型（$ user）

Form::model($user, array('route' => array('user.update', $user->id)))

Is just any record you need to, if you have more than one table involved, you'll have to do something like 只需要你需要的任何记录，如果你涉及多个表，你就必须做类似的事情

$user = User::where('id',$userID)
           ->leftJoin('users_addresses', 'users_addresses.user_id', '=', 'users.id')
           ->first();

And pass this composed model to your Form::model(). 并将此组合模型传递给Form :: model（）。

How you name your inputs is entirely up to you, because you'll have to write the logic to process your form. 如何命名输入完全取决于您，因为您必须编写处理表单的逻辑。 But, in my opinion users_address[street] for the address inputs is good, because you'll end up with an array of addresses columns that you can pass right away to your UserAddress model. 但是，在我看来，地址输入的users_address[street]是好的，因为你最终会得到一个地址数组列，你可以立即传递给你的UserAddress模型。

<html>
    <head>
        <title></title>
    </head>
    <body>
        {{ Form::model($user, array('route' => array('user.update', $user->id))) }}
            {{ Form::label('first_name', 'First Name:', array('class' => 'address')) }}
            {{ Form::text('first_name') }}

            {{ Form::label('last_name', 'Last Name:', array('class' => 'address')) }}
            {{ Form::text('last_name') }}

            {{ Form::label('email', 'E-Mail Address', array('class' => 'address')) }}
            {{ Form::text('email') }}

            {{ Form::label('address[street1]', 'Address (Street 1)', array('class' => 'address')) }}
            {{ Form::text('address[street1]') }}

            {{ Form::label('address[street2]', 'Address (Street 2)', array('class' => 'address')) }}
            {{ Form::text('address[street2]') }}

            {{ Form::label('ddress[city]', 'City', array('class' => 'address')) }}
            {{ Form::text('address[city]') }}

            {{ Form::label('address[state]', 'State', array('class' => 'address')) }}
            {{ Form::text('address[state]') }}

            {{ Form::label('address[zip]', 'Zip Code', array('class' => 'address')) }}
            {{ Form::text('address[zip]') }}

            {{ Form::submit('Send this form!') }}
        {{ Form::close() }}
    </body>
</html>

And if you do dd( Input::all() ) in your controller, you'll get something like this: 如果你在你的控制器中做dd( Input::all() ) ，你会得到这样的东西：

这是Input :: all（）结果 This result is provided by Kint's dd(): https://github.com/raveren/kint . 这个结果由Kint的dd（）提供： https ： //github.com/raveren/kint 。 Really helpful. 真有帮助。

If your form just have fields from a single Model, your update method can be very simple and look something like: 如果您的表单只包含单个模型中的字段，那么您的更新方法可以非常简单，如下所示：

public function update($id)
{
    $user = User::find($id);

    if (!$user->update(Input::all())) {
        return Redirect::back()
                ->with('message', 'Something wrong happened while saving your model')
                ->withInput();
    }

    return Redirect::route('user.saved')
                ->with('message', 'User updated.');
}

On forms a little bit more complex, coders will have to add more logic to their controllers, in you case with a little bit more of research I think you can make this happen: 在表单上稍微复杂一些，编码器必须为他们的控制器添加更多的逻辑，在你的情况下进行更多的研究我认为你可以做到这一点：

public function update($id)
{
    $user = User::find($id);

    $inputs = Input::all();

    if (!$user->update($inputs)) {
            $address = new UserAddress($inputs['address']);

        $user->address()->save($address);

        ...
    }

    ...
}

Answer 2

In Laravel 5.1 for relation model binding you just need to eager load relation table(s): 在Laravel 5.1中，关系模型绑定只需要加载关系表：

$user = User::with(['address'])->find($id);

And in view set fields names as array: 并在视图中将字段名称设置为数组：

{!! Form::model($user, ['route' => ['user.update', $user->id]]) !!}
    {!! Form::text('address[street]') !!}
    {!! Form::text('address[number]') !!}
{!! Form::close() !!}

Laravel形式模型绑定

问题描述

2 个解决方案

解决方案1
43 已采纳 2013-06-01 16:02:00

解决方案2
2 2015-11-19 15:10:29

Laravel形式模型绑定

问题描述

2 个解决方案

解决方案1 43 已采纳 2013-06-01 16:02:00

解决方案2 2 2015-11-19 15:10:29

解决方案1
43 已采纳 2013-06-01 16:02:00

解决方案2
2 2015-11-19 15:10:29