[英]C++ function to return current date (with zeros in month and day)
I have this C++ function: 我有这个C ++函数:
string date()
{
time_t seconds = time (NULL);
struct tm * timeinfo = localtime (&seconds);
ostringstream oss;
oss << (timeinfo->tm_year + 1900) << "-" << (timeinfo->tm_mon + 1) << "-" << timeinfo->tm_mday;
string data = oss.str();
return data;
}
The problem is I wanted the month and day with 0's. 问题是我想要0和0的月和日。 It's returning '2013-6-1' instead of '2013-06-01'
它正在回归'2013-6-1'而不是'2013-06-01'
I'm trying to get this right with some if's and else's but I'm not getting anywhere.. 我试图用一些if和其他的方式做到这一点,但我没有得到任何地方..
Could you please help me? 请你帮助我好吗?
You can use the two stream modifiers std::setw
and std::setfill
with appropriate settings, for instance you can change your code to read: 您可以使用两个流修饰符
std::setw
和std::setfill
进行适当的设置,例如,您可以将代码更改为:
string date()
{
time_t seconds = time (NULL);
struct tm * timeinfo = localtime (&seconds);
ostringstream oss;
oss << (timeinfo->tm_year + 1900) << "-" << std::setw(2) << std::setfill('0') << (timeinfo->tm_mon + 1) << "-" << std::setw(2) << std::setfill('0') << timeinfo->tm_mday;
string data = oss.str();
return data;
}
You can also use std::put_time , though not implemented in gcc 4.7: 你也可以使用std :: put_time ,虽然没有在gcc 4.7中实现:
std::string date()
{
time_t seconds = time (NULL);
struct tm * timeinfo = localtime (&seconds);
std::ostringstream oss;
oss << std::put_time(&timeinfo, "%Y-%m-%d");
// or: oss << std::put_time(&timeinfo, "%F");
return oss.str();
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.