NOTEPAD ++ REGEX如何替换和删除$ 0中的空格

Question

I'm using this regex:

\s[0-9]+ thd

It finds what I want perfectly. I want to remove the white space at the beginning. What should I put in the replace field?

Answer 1

将搜索文本更改为\\s([0-9]+ thd) ，然后根据正则表达式的类型将替换ID更改为\\1或$1 。

Answer 2

Find:

\s([0-9]+ thd)

Replace:

$1

Answer 3

So if you using Notepad++ everything in parenthesis refers to section build from \\ and number in Replace box. Look at example:

    Find: (\s)([0-9]+ thd)
    Replace: \1\2

This give you back first \\1 and second \\2 section - nothing unusual, but when you live only \\2 after replace you'll get only part found by ([0-9]+ thd)

Going further if you split your expression to (\\s)([0-9]+)(\\s)(thd) then you'll get 4 parts

This parts will be represented by \\1\\2\\3\\4 and if you need add something more to your output line:

for example added_text_before\\1added_text_after in Replace will result merging added text and section found - practice because there is no hidden magic out there.

Remember that using regex in Notepad++ have some limitations (to long expression aren't read).