[英]PHP - MySQL create a tree view from product table
I have a category table as follows. 我有一个类别表如下。 Which I am saving category, subcategories in that table ( Multiple sub-categories ).
我在该表中保存类别,子类别(多个子类别)。 My table looks like
我的桌子看起来像
id | name | parent_of | created_on
-------+---------------+---------------+---------------------
1 | Name 1 | 0 | 2013-05-1 00:00:00
-------+---------------+---------------+---------------------
2 | Name 2 | 0 | 2013-05-1 00:00:00
-------+---------------+---------------+---------------------
3 | Name 3 | 1 | 2013-05-1 00:00:00
-------+---------------+---------------+---------------------
4 | Name 4 | 1 | 2013-05-1 00:00:00
-------+---------------+---------------+---------------------
5 | Name 5 | 3 | 2013-05-1 00:00:00
-------+---------------+---------------+---------------------
6 | Name 6 | 3 | 2013-05-1 00:00:00
-------+---------------+---------------+---------------------
Now I need to query this table and create a tree structure as follows to make a easy navigation through categories in front end. 现在,我需要查询此表并创建一个树结构,如下所示,以便轻松浏览前端的类别。
A tree like follows 一棵树如下
1
|--> 3
| |--> 5
| |--> 6
|--> 4
2
I am bit confused about the query. 我对查询感到有点困惑。 Can anyone please help me ?
谁能帮帮我吗 ?
Thanks in advance 提前致谢
For basic display, you may use: 对于基本显示,您可以使用:
SELECT * FROM `Table` WHERE `parent_of` = 0;
It will give you all the root nodes. 它将为您提供所有根节点。
When user click on a node, he / she / it submits request to the server (Ajax maybe) to fetch child nodes for clicked one, like: 当用户单击某个节点时,他/她/它会向服务器提交请求(可能是Ajax)以获取点击的节点的子节点,如:
$node = abs((int)$_GET['node']);
then: 然后:
SELECT * FROM `Table` WHERE `parent_of` = {$node};
Please try the below code logic for your solution, 请为您的解决方案尝试以下代码逻辑,
$result = mysql_query("SELECT id, parent_of FROM category WHERE parent_of > 0");
$treeStructure = array();
while($row = mysql_fetch_array($result)) {
$id = $row['id'];
$parentID = $row['parent_of'];
$treeStructure[$parentID][] = $treeStructure[$id];
}
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