如何在Java中传递参数

Question

Hi i am using this code to run the shell script.the thing is i want to pass argument "trng-java" while i am running program.like this

like java Classname trng-java

code:

import java.io.*;

public class Test
{


public static void main(String[] args)
{
    try {
        Runtime rt = Runtime.getRuntime();
        Process pr = rt.exec(new String[]{"/bin/sh", "/tmp/test.sh", "trng-java"});

        BufferedReader input = new BufferedReader(new InputStreamReader(pr.getInputStream()));
        String line = "";
        while ((line = input.readLine()) != null) {
            System.out.println(line);
        }
    } 
    catch (Exception e) {
        System.out.println(e.toString());
        e.printStackTrace();
    }
}
}

How to do this?

Answer 1

您传入的参数将在args参数中以String yourParam = args [0]的形式出现

Answer 2

命令行参数通过String []参数args传递到您的应用程序，因此您应该能够使用args[0]访问该值。

Process pr = rt.exec(new String[]{"/bin/sh", "/tmp/test.sh", args[0] });

Answer 3

Process pr = rt.exec(new String[]{"/bin/sh", "/tmp/test.sh", args[0]});

当然，您还需要检查args是否包含至少一个参数

Answer 4

When you pass arguments to a java application, they are accessible through the args[] array in main.

See: http://docs.oracle.com/javase/tutorial/essential/environment/cmdLineArgs.html which I am quoting:

Echoing Command-Line Arguments

The Echo example displays each of its command-line arguments on a line by itself:

 public class Echo { public static void main (String[] args) { for (String s: args) { System.out.println(s); } } } 

The following example shows how a user might run Echo. User input is in italics.

 java Echo Drink Hot Java Drink Hot Java 

Parsing Numeric Command-Line Arguments

If an application needs to support a numeric command-line argument, it must convert a String argument that represents a number, such as "34", to a numeric value. Here is a code snippet that converts a command-line argument to an int:

 int firstArg; if (args.length > 0) { try { firstArg = Integer.parseInt(args[0]); } catch (NumberFormatException e) { System.err.println("Argument" + " must be an integer"); System.exit(1); } } 

Answer 5

只需将参数添加到您的命令中，如下所示：

rt.exec("/bin/sh /tmp/test.sh trng-java");

Answer 6

in public static void main(String[] args) the args parameter is the arguement. If you use multiple arguement like

java Classname a b c

Then in your main method args will be an array containing a,b,c

if this is what you want then args[0] is the preferred arguement.