Java中是否可能有一个不使用关系运算符的if语句？

Question

This isn't for a specific code, I'm just curious. Relational operators as in == , < , > , >= , <= , != .

Answer 1

Of course:

if (processing)
{
    // enter if the boolean processing is true
}

Answer 2

Lets say you have a function that returns a boolean value

  public boolean isTrue()
  {
    //Some code
    //return true or false

  }

Then the 'if' statement will look something like this:

  if(isTrue())
     //Do something
  else
    //Do something else

Answer 3

Well actually,, the if statement only know wether if it is a true or false value.
But in case of integer, it returnx true if what inside bracket is correct.
Like:

int n=10;  
if(n==10){}

The value inside bracket will return true since it is correct. Return false if you change the bracket into n>10

Different condition goes for String..

Answer 4

Yes:

if (x) {
    ...
}

or

if (!x) {
    ...
}

where x is a boolean or anything that returns a boolean.

Heck, go crazy:

boolean x = false, y = false;

if (x = y = x = !y) {

}

(notice that we're using = not == here - you would probably very rarely want to do something like this, if ever.)

Answer 5

Yes. Generally speaking, the syntax of an if statement is if (cond) { xxx(); } if (cond) { xxx(); } where cond is any expression which evaluate to a boolean .

Which means the following are all valid:

if (true)           // Literal value true
if (m.find())       // m is a Matcher; .find() returns true if match
if (3 <= 3)         // operator
if (a && b)         // a and b are expressions evaluating to a boolean;
                    // && is the logical "and" operator

And so on.