从sql数据库插入值到html表
[英]insert value from sql database to html table
问题描述
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<table id="users" border="1">
<tr>
<td>ID</td>
<td>Name</td>
<td>Age</td>
<td>Email</td>
<td>DOB</td>
</tr>
<tr>
<td>1</td>
<td><input size=25 type="text" id="Name" readonly=true/></td>
<td><input size=10 type="text" id="Age" readonly=true/></td>
<td><input size=25 type="text" id="Email" readonly=true/></td>
<td><input size=10 type="date" id="DOB" readonly=true/></td>
</tr>
</table>
<?php
$con = mysql_connect("127.0.0.1","root","test") or die(mysql_error());
$db = mysql_select_db("lr") or die(mysql_error());
$sql=mysql_query("SELECT * FROM user ")or die(mysql_error());
$count=0;
while($row = mysql_fetch_array($sql))
{
$name=$row['Name'];
$age=$row['age'];
$email=$row['Email'];
$dob=$row['DOB'];
echo '<table id="users" border="">
<tr>
<td>$count</td>
<td>$name</td>
<td>$age</td>
<td>$email</td>
<td>$dob</td>
</tr>
</table> ';
$count++;
}
?>
<form id="form1" name="form1" method="post" action="add.php">
<input type="submit" name="Add" id="Add" value="Add" />
<input type="submit" name="Remove" id="Remove" value="Remove" />
<input type="submit" name="Edit" id="Edit" value="Edit" />
</form>
</body>
</html>
this is what i have tried also have retrieved data from mysql database but unable to show it on my html table. 
这是我试过也从mysql数据库中检索数据但无法在我的html表上显示它。 the above code does everything except showing values on the table. 除了在表上显示值之外，上面的代码执行所有操作。 do check the while loop that print value to the table 检查打印值到表的while循环
3 个解决方案
解决方案1
2 已采纳 2013-06-04 12:58:16
Try like this 试试这样吧
echo '<table id="users" border="">';
while($row = mysql_fetch_array($sql))
{
$name=$row['Name'];
$age=$row['age'];
$email=$row['Email'];
$dob=$row['DOB'];
echo
'<tr>
<td>'.$count.'</td>
<td>'.$name.'</td>
<td>'.$age.'</td>
<td>'.$email.'</td>
<td>'.$dob.'</td>
</tr>';
$count++;
}
echo ' </table> ';
And try to use mysqli_* functions or PDO statements due to the mysql_* functions are deprecated. 并尝试使用mysqli_ *函数或PDO语句，因为不推荐使用mysql_ *函数。
解决方案2
0
Variables inside of single-quoted strings aren't expanded. 单引号字符串中的变量不会扩展。
Note: Unlike the double-quoted and heredoc syntaxes, variables and escape sequences for special characters will not be expanded when they occur in single quoted strings.
You have to use double-quotes around your string, then single-quotes around your HTML properties inside of the string. 您必须在字符串周围使用双引号，然后在字符串内部的HTML属性周围使用单引号。
while($row = mysql_fetch_array($sql))
{
$name=$row['Name'];
$age=$row['age'];
$email=$row['Email'];
$dob=$row['DOB'];
echo "<table id='users' border=''>
<tr>
<td>$count</td>
<td>$name</td>
<td>$age</td>
<td>$email</td>
<td>$dob</td>
</tr>
</table>";
解决方案3
0 2013-06-04 13:32:21
Once check $sql query getting the rows by putting print_r($row); 检查$sql查询后通过print_r($row);获取行print_r($row); in while loop after that do some modifications in while loop 在while循环之后，在while循环中做一些修改
while($row = mysql_fetch_array($sql)){
echo "<table id='users' border=''>
<tr>
<td>".$count."</td>
<td>".$row['Name']."</td>
<td>".$row['age']."</td>
<td>".$row['Email']."</td>
<td>".$row['DOB']."</td>
</tr> </table>"; $count++; }
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