带有SQLite的Python。 SQLite数据变成变量

Question

SQLite in python, print it on screen, python 3.2.4

I have this code

cur.execute("SELECT * FROM Player")
while True:

    row = cur.fetchone()
    print(row)
    print("why  {0}".format(cur.fetchone()))

    if row == None:
        break

and i receive this output: Load from databases

    (1, 'Damian', 1, 15, 18, 100, 100)
    why  None
    None
    why  None

((( (1, 'Damian', 1, 15, 18, 100, 100) )) <-- this is in my database. why when i try to print out in another print it doesnt works ? or when i try to print like this : print(row[0]) it shows error like = print(row[0]) TypeError: 'NoneType' object is not subscriptable

Answer 1

Your problem is that you are calling fetchone() two times inside the loop. There is nothing magical about the while loop that corresponds to rows; instead it is a side effect of the call to fetchone() that advances to the next result row.

The first print outputs the first row; the second (with "why" ) would print the second row (if it existed).