无法将 C# 的默认日期时间插入到 SQL Server 2008

Question

I'm working on a C# console application project. Trying to insert a DateTime value into SQL Server 2008 and this is working good. In case if my code fails I want to insert the default DateTime to the table in database.

When I tried to insert I got an error.

SqlTypeException was unhandled:
SqlDateTime overflow. Must be between 1/1/1753 12:00:00 AM and 12/31/9999 11:59:59 PM.

Below I have pasted the specific code.

try
{
  ...
  return DateTime.Now;
}

catch (WebException ex)
{
  ...
  return default(DateTime);
}

Code I used to insert details in the LOGS table:

connection.Open();
for (int i = 0; i < LogList.Count; i++)
    {
        string aprocessLogQuery = "INSERT INTO PROCESS_LOGS VALUES (@fileId, @startTime, @endTime, @transferredTime)";
        command = new SqlCommand(aprocessLogQuery, connection);
        command.Parameters.Add("fileId", SqlDbType.Int).Value = LogList[i].fileId;
        command.Parameters.Add("startTime", SqlDbType.DateTime).Value = LogList[i].fileGeneration_StartDateTime;
        command.Parameters.Add("endTime", SqlDbType.DateTime).Value = LogList[i].fileGeneration_EndDateTime;
        command.Parameters.Add("transferredTime", SqlDbType.DateTime).Value = LogList[i].fileTransferred_DateTime;
        dataReader.Close();
        dataReader = command.ExecuteReader();
    }
connection.Close();

The default value of DateTime is 01/01/0001 12:00:00 AM , therefore it is not working. Can anyone please suggest alternate working solution?

Thanks

Answer 1

Another alternative solution is you can work around by build extension method look like as below:

public static class DateTimeExtension
{
    public static DateTime DefaultSqlDateTime(this DateTime dateTime)
    {
       return new DateTime(1753, 1, 1, 12, 0, 0);
    }
}

and instead of return default(DateTime) you can use variable dateTime return dateTime.DefaultSqlDateTime;

EDIT: How to use extension method:

Eg: return default(DateTime).GetDefaultSqlDateTime();

or

DateTime dateTime = ...
return dateTime.GetDefaultSqlDateTime();

Answer 2

In the database, an unknown date is represented with NULL value. You can insert that like:

command.Parameters.AddWithValue("@startTime", DBNull.Value);

(As far as I know, it's required to prefix your parameters with @ .)

Answer 3

I am using this function in my Utilities instead of regular TryParse

public static bool TryParseSqlDateTime(string someval, DateTimeFormatInfo dateTimeFormats, out DateTime tryDate)
    {
        bool valid = false;
        tryDate = (DateTime)System.Data.SqlTypes.SqlDateTime.MinValue;
        System.Data.SqlTypes.SqlDateTime sdt;
        if (DateTime.TryParse(someval, dateTimeFormats, DateTimeStyles.None, out tryDate))
        {
            try
            {
                sdt = new System.Data.SqlTypes.SqlDateTime(tryDate);
                valid = true;
            }
            catch (System.Data.SqlTypes.SqlTypeException ex)
            {


            }
        }

        ret

Answer 4

You can use this, this will return minimum date value that SQL will accept. This method return DateTime in .Net.

System.Data.SqlTypes.SqlDateTime.MinValue.Value