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Json:使用Gson库时反序列化错误

[英]Json: Deserialization error while using Gson library

I have json string that should be converted back to a Map type. 我有json字符串应该转换回Map类型。

Json used: Json使用:

 String jsonString = "{
    "varA": "<math><mrow><mn>8</mn></mrow></math>",
    "varB": "<math><mrow><mi>m</mi></mrow></math>",
    "ans": "<math><mrow><mn>8</mn><mo>&#8290;</mo><mi>m</mi></mrow></math>"
 }"

Code that converts json to Map: 将json转换为Map的代码:

Map<String, String> variableMap = gson.fromJson(jsonString, new TypeToken<Map<String,String>>(){}.getType());

Error: 错误:

[ERROR] The JsonDeserializer StringTypeAdapter failed to deserialize json object {"varA":"<math><mrow><mn>8</mn></mrow></math>","varB":"<math><mrow><mi>m</mi></mrow></math>","ans":"<math><mrow><mn>8</mn><mo>&#8290;</mo><mi>m</mi></mrow></math>"} given the type class java.lang.String

I know it has something to do with the type, but I have indicated that the type will be String explicitly in the type token. 我知道它与类型有关,但我已经指出类型将在类型标记中显式为String。

The gson object is declared as follows: gson对象声明如下:

Gson gson = new GsonBuilder().disableHtmlEscaping().create();

You have to escape the quotes that delimit the JSON string values contained within your Java string. 您必须转义分隔Java字符串中包含的JSON字符串值的引号。 In fact your example is not a valid Java program - Java lacks multi-line strings, for starters. 实际上你的例子不是一个有效的Java程序 - 对于初学者来说,Java缺少多行字符串。

The following snippet runs just fine (angle brackets and the Unicode character turn out to be innocuous): 以下代码段运行得很好(尖括号和Unicode字符结果是无害的):

public static void main(String[] args) {
         String jsonString = "{\"varA\": \"<math><mrow><mn>8</mn></mrow></math>\", \"varB\": \"<math><mrow><mi>m</mi></mrow></math>\", \"ans\": \"<math><mrow><mn>8</mn><mo>&#8290;</mo><mi>m</mi></mrow></math>\"}";
         Map<String, String> variableMap = new Gson().fromJson(jsonString, new TypeToken<Map<String,String>>(){}.getType());
         System.out.println("foo");
    }

It is working when you use Map.class instead of new TypeToken<Map<String,String>>(){}.getType() . 当您使用Map.class而不是新的TypeToken<Map<String,String>>(){}.getType()时,它正在工作。 See my little example: 看我的小例子:

Gson gson = new GsonBuilder().disableHtmlEscaping().create();

Map<String, String> map = new HashMap<String, String>();
map.put("varA", "<math><mrow><mn>8</mn></mrow></math>");
map.put("varB", "<math><mrow><mi>m</mi></mrow></math>");
map.put("ans", "<math><mrow><mn>8</mn><mo>&#8290;</mo><mi>m</mi></mrow></math>");

String json = gson.toJson(map);

System.out.println(json);
System.out.println(gson.fromJson(json, Map.class));

It prints: 它打印:

{
   "varB":"<math><mrow><mi>m</mi></mrow></math>",
   "ans":"<math><mrow><mn>8</mn><mo>&#8290;</mo><mi>m</mi></mrow></math>",
   "varA":"<math><mrow><mn>8</mn></mrow></math>"
}

{varB=<math><mrow><mi>m</mi></mrow></math>, ans=<math><mrow><mn>8</mn><mo>&#8290;</mo><mi>m</mi></mrow></math>, varA=<math><mrow><mn>8</mn></mrow></math>}

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