比较两个文件夹上具有相似名称的文件内容

Question

I have two folders (I'll use database names as example):

• MongoFolder/
• CassandraFolder/

These two folders have similar files inside like:

• MongoFolder/

  • MongoFile
  • MongoStatus
  • MongoConfiguration
  • MongoPlugin

• CassandraFolder/

  • CassandraFile
  • CassandraStatus
  • CassandraConfiguration

Those files have content also very similar, only changing the name of the database for example, so they all have code or configuration only changing the name Mongo for Cassandra .

How can I compare this two folders, so the result is the files missing from one to the other (for example the file CassandraPlugin for the CassandraFolder ) and also that the contents of the files alike, have to be similar, only changing the database name.

Answer 1

This will give you the names of the missing files (minus the database name):

find MongoFolder/ CassandraFolder/ | \
      sed -e s/Mongo//g -e s/Cassandra//g | sort | uniq -u

Output:

Folder/Plugin

Answer 2

the following provides a full diff, including missing files and changed content:

cp -r CassandraFolder cmpFolder
# rename files
find cmpFolder -name "Cassandra*" -print | while read file; do
    mongoName=`echo "$file" | sed 's/Cassandra/Mongo/'`
    mv "$file" "$mongoName"
done
# fix content
find cmpFolder -type f -exec perl -pi -e 's/Cassandra/Mongo/g' {} \;

# inspect result
diff -r MongoFolder cmpFolder # or use a gui tool like kdiff3

I haven't tested this though, feel free fix bugs or to ask if something specific is unclear. Instead of mv you can also use rename but that's different on different flavours of linux.