[英]How to get the list elements using list inside another list in java
I have a list like this List contains set of dtime,uptime values.I want to get the list items ie, dtime into one and uptime into another variable.Likewise I want to get all the dtime and uptime pair values seperatly into the variables using for loop in java.How can I achieve this.Is it possible list or vector?Please help me. 我有一个像这样的列表列表包含一组dtime,正常运行时间值。我想得到列表项,即dtime为一个和正常运行时间到另一个变量。我希望得到所有的dtime和正常运行时间对值分离到变量使用for循环在java.How我可以实现这个。它可能列表或向量吗?请帮助我。 Pseudo code
伪代码
List.get(0).get(0)-->gives 1st dtime
List.get(0).get(1)-->gives 1st uptime
List.get(1).get(0)-->gives 2nd dtime
List.get(1).get(1)-->gives 2nd uptime
And so on.. 等等..
How to implement this with for loop I am not getting.I am new to java>please help me.. 如何用for循环实现这个我没有得到。我是java的新手>请帮帮我..
First Convert That ArrayList into Object[] array then get the value like given below code...driver_ModelsObj is an array convert that into drives object array then get the value from inside the array. 首先将ArrayList转换为Object []数组然后获取类似下面代码的值... driver_ModelsObj是一个数组转换成驱动器对象数组然后从数组内部获取值。
for(int indx=0;indx<driver_ModelsObj.size();indx++){
Object[] drivers=(Object[]) driver_ModelsObj.get(indx);
String Device_ID=drivers[0].toString();
}
You can try this ,Let say you have variables like 你可以尝试这个,假设你有变量
double dtime;
Timestamp tp;
And listofresults is coming from query results. listofresults来自查询结果。
listofresults = results.getResultList();
If list is coming from query then put it in the loop this way in the condition of for loop 如果list来自查询,那么在for循环的条件下将它放入循环中
for(int i=0;i< listofresults.size() ;i=i+2)
{
dtime=(double) listofresults.get(i);
//cast because the value is of object type
tp=(TimeStamp) listofresults.get(i+1);
//cast because the value is of object type
//do something with these variables
}
Sounds like you could use a domain object containing uptime
and downtime
. 听起来你可以使用包含
uptime
和downtime
的域对象。
For example, 例如,
public class Stats {
int dtime;
int uptime;
}
Then you can have a List<Stats>
and access it like this: 然后你可以有一个
List<Stats>
并像这样访问它:
mylist.get(0).dtime
mylist.get(0).uptime
mylist.get(1).dtime
mylist.get(1).uptime
Part of the (newer) Collcetions framework, List
is almost always a better alternative than Vector
作为(较新的)Collcetions框架的一部分,
List
几乎总是比Vector
更好的选择
List.get(0).get(0)-->gives 1st dtime
List.get(0).get(1)-->gives 1st uptime
Well, what you're doing here, is getting the list at position 0
, and getting item 1
from that list. 那么,你在这里做的是将列表放在第
0
,并从该列表中获取第1
项。 In a for loop
we can express this as: 在
for loop
我们可以将其表达为:
for(int x = 0; x < List.size(); x++)
{
for(int y = 0; y < List.get(x).size(); y++)
{
if(y % 2 == 0)
{
// It's a dtime object.
}
else
{
// It's an uptime object.
}
}
}
Before this, you could declare some lists of your own: 在此之前,您可以声明一些自己的列表:
List<DTime> listD = new ArrayList<ATimeObject>();
List<UpTime> listUp = new ArrayList<UpTime>();
Now when you're cycling through, all you need to do is add the relevant object: 现在,当您骑车时,您需要做的就是添加相关对象:
if(y % 2 == 0)
{
listD.add(List.get(x).get(y));
}
else
{
listUp.add(List.get(x).get(y));
}
You should create a POJO like 你应该创建一个POJO
public class TimeData {
double dtime;
Date uptime;
}
Then add each POJO to array list and then iterate it. 然后将每个POJO添加到数组列表中,然后迭代它。
List<TimeData> oList = new ArrayList<TimeData>();
int nSize = oList.size();
for(int i=0;i<nSize;i++){
TimeData child = oList.get(i);
// get value using getters
}
I recommend creating a wrapper for it. 我建议为它创建一个包装器。
public class UpTimeDownTime {
MyTimeDataClass downtime;
MyTimeDataClass uptime;
public UpTimeDownTime(MyTimeDataClass downtime, MyTimeDataClass uptime){
this.downtime = downtime;
this.uptime = uptime;
}
public MyTimeDataClass getDowntime () {
return downtime;
}
public MyTimeDataClass getUptime () {
return uptime;
}
public static void main (String[] args) {
List<List<MyTimeDataClass>> List = ...;
List<UpTimeDownTime> uptimeDowntime = new ArrayList<UpTimeDownTime>();
for(List<MyTimeDataClass> timeList : List){
UpTimeDownTime u = new UpTimeDownTime(timeList.get(0), timeList.get(1));
uptimeDowntime.add(u);
}
}
}
If your list is as below 如果您的清单如下
List list = [[1],[2],[3]];
We can retrieve the each value as below. 我们可以检索每个值,如下所示。
((List)list.get(0)).get(0); //This will retrieve value 1
((List)list.get(1)).get(0); //This will retrieve value 2
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