jQuery ajax成功回调函数-如何使其匿名？

Question

I am unable to get the success callback to work in a jQuery ajax call. The following code calls interpretResponse() just fine, but of course resultJSON is undefined :

        var that = this;
        jQuery('#fsForm1492441').submit(function(event) {
            event.preventDefault();
            jQuery.ajax({ type: "POST",
                url: "format_result.php",
                data: jQuery(this).serialize(),
                success: that.interpretResponse(),
                dataType: "json"
            });
        });

        function interpretResponse(resultJSON) {
        // code here to handle resultJSON
        }

I want something like:

                success: function(resultJSON) { 
                         that.interpretResponse(resultJSON); 
                         },

How should the success callback be written?

Answer 1

just do this :

success: interpretResponse,

your code will look like this -

var that = this;
jQuery('#fsForm1492441').submit(function (event) {
    event.preventDefault();
    jQuery.ajax({
        type: "POST",
        url: "format_result.php",
        data: jQuery(this).serialize(),
        success: interpretResponse,
        dataType: "json"
    });
});

function interpretResponse(resultJSON) {
    // code here to handle resultJSON
}

Answer 2

The answer above was correct, but it turned out that I was dealing with a different problem. The weird bug in FireFox that keeps ajax calls from getting past readyState 1 was causing the callback function to not load. I ended up using the workaround described here: Ajax won't get past readyState 1, why? Basically getting Firefox to set the callback onload rather than onreadystatechange .

Thanks to pXL for the answer to the question the way I asked it.