[英]Syntax error (missing operator) in query expression (ms access)
I am trying to run this code to access however it is giving me this error. 我正在尝试运行此代码进行访问,但是它给了我这个错误。 I check other sites with related problem and it state that I need to put a parenthesis if there is 2 more joins. 我检查了其他具有相关问题的站点,并且指出如果还有2个连接,则需要加括号。 I been trying but no luck. 我一直在尝试,但没有运气。
select *
from
(
select group_id from tbl_group
union
select group_id from table_group\website
)a
left outer join tbl_group on a.group_id = tbl_group.group_id
left outer join table_group\website on a.group_id=table_group\website.group_id;
How can you "select tbl_group.group_id from t1" and "select tbl_group.group_id from t2"? 如何“从t1选择tbl_group.group_id”和“从t2选择tbl_group.group_id”? t1 and t2 dont have any reference to tbl_group. t1和t2没有对tbl_group的引用。 I think you're aliasing your tables all wrong. 我认为您对表格的别名都是错误的。
When I compare your code with the link you provided, I don't see where you're pulling t1 and t2 from. 当我将您的代码与您提供的链接进行比较时,看不到您要从哪里提取t1和t2。
I think it should be tbl.group instead 我认为应该改为tbl.group
SELECT A.*, tbl_group.group_id AS Col1, [table_group\website].group_id AS Col2
FROM ([SELECT group_id FROM tbl_group
UNION
SELECT group_id FROM table_group\website]. AS A LEFT JOIN tbl_group ON A.group_id = tbl_group.group_id) LEFT JOIN [table_group\website] ON A.group_id = [table_group\website].group_id;
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