[英]Convert IEnumerable<Task<T>> to IObservable<T>
I'm trying to use the Reactive Extensions (Rx) to buffer an enumeration of Tasks as they complete. 我正在尝试使用Reactive Extensions(Rx)在任务完成时缓冲它们的枚举。 Does anyone know if there is a clean built-in way of doing this? 有谁知道是否有一个干净的内置方式这样做? The ToObservable
extension method will just make an IObservable<Task<T>>
, which is not what I want, I want an IObservable<T>
, that I can then use Buffer
on. ToObservable
扩展方法只会生成一个IObservable<Task<T>>
,这不是我想要的,我想要一个IObservable<T>
,然后我就可以使用Buffer
了。
Contrived example: 举例:
//Method designed to be awaitable
public static Task<int> makeInt()
{
return Task.Run(() => 5);
}
//In practice, however, I don't want to await each individual task
//I want to await chunks of them at a time, which *should* be easy with Observable.Buffer
public static void Main()
{
//Make a bunch of tasks
IEnumerable<Task<int>> futureInts = Enumerable.Range(1, 100).Select(t => makeInt());
//Is there a built in way to turn this into an Observable that I can then buffer?
IObservable<int> buffered = futureInts.TasksToObservable().Buffer(15); //????
buffered.Subscribe(ints => {
Console.WriteLine(ints.Count()); //Should be 15
});
}
You can use the fact that Task
can be converted to observable using another overload of ToObservable()
. 您可以使用以下事实:可以使用ToObservable()
另一个重载将Task
转换为observable。
When you have a collection of (single-item) observables, you can create a single observable that contains the items as they complete using Merge()
. 当您拥有(单项)可观察对象的集合时,您可以使用Merge()
创建一个包含完成项目的observable。
So, your code could look like this: 所以,你的代码看起来像这样:
futureInts.Select(t => t.ToObservable())
.Merge()
.Buffer(15)
.Subscribe(ints => Console.WriteLine(ints.Count));
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