[英]send a variable from a perl script into a command line
I have a perl script that always returns yesterday's date and the date is stored on a variable called $yesterday
我有一个Perl脚本,该脚本始终返回昨天的日期,并且该日期存储在名为
$yesterday
的变量中
Now, I am running that perl script using cmd prompt. 现在,我使用cmd提示符运行该Perl脚本。 After it figures out what yesterday's date was I would like to pass $yesterday somehow into the cmd line so that it can open up a "$yesterday.txt" file.
在确定了昨天的日期之后,我想以某种方式将$ yesterday传递到cmd行中,以便它可以打开“ $ yesterday.txt”文件。 The txt files are already there and match the date format in the filename.
txt文件已经存在,并且与文件名中的日期格式匹配。
Are you asking how to open
a file? 您在问如何
open
文件吗?
my $file = "$yesterday.txt";
open my $fh, "<", $file or die "Cannot open $file for reading: $!";
See the documentation for more information on the open
command. 有关
open
命令的更多信息,请参见文档 。
You can simply include the $variable in the string of the command or use string concatenation to put the static and variable parts together: 您可以简单地在命令的字符串中包含$ variable或使用字符串串联将静态和可变部分放在一起:
system("echo yesterday >$yesterday.txt");
or 要么
system("echo yesterday >" . $yesterday . ".txt");
The above calls a commandline program or command from perl and the command includes the value of your $yesterday variable. 上面的代码从perl调用命令行程序或命令,并且该命令包含$ yesterday变量的值。
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