[英]Iterating the LinkedHashMap shows compilation error
Below is the code for AttributeValue class- 以下是AttributeValue类的代码-
@JsonSerialize(include=JsonSerialize.Inclusion.NON_NULL)
@JsonIgnoreProperties(ignoreUnknown=true)
public class AttributeValue<T> {
private T value; // value
private Date timestamp; // timestamp
String valueType = null; // class type of the value object
@Deprecated
private int classNumber = 0; // internal
private static Logger s_logger = Logger.getInstance(BEAttributeValue.class);
@JsonProperty("v")
public T getValue() {
if (valueType != null && !value.getClass().getName().equalsIgnoreCase(valueType)) {
value = convert(value, valueType);
}
return value;
}
@JsonProperty("v")
public void setValue(T value) {
this.value = value;
}
private T convert(Object other, String classType) {
T value = null;
if (other != null) {
IJsonMapper mapper = JsonMapperFactory.getInstance().getJsonMapper();
try {
String json = mapper.toJson(other);
Class<T> className = (Class<T>)Class.forName(classType);
value = mapper.toPojo(json, className);
} catch (Exception e) {
s_logger.log(LogLevel.ERROR, "BEAttributeValue::convert(), caught an exception: \n",e.getStackTrace());
}
}
return value;
}
}
Problem Statement:- 问题陈述:-
Now I am trying to iterate over the list of AttributeValue
with the below code- 现在,我尝试使用以下代码遍历
AttributeValue
的列表:
for(AttributeValue<?> al: list) {
System.out.println(al.getValue());
}
When I inspect on al
, I see value as LinkedHashMap<K,V>
and when I print al.getValue()
, it gives me this- 当我检查
al
,我看到的值为LinkedHashMap<K,V>
,当我打印al.getValue()
,它给了我-
{predictedCatRev=0;101;1,1;201;2, predictedOvrallRev=77;2,0;1,16;3, sitePrftblty=77;2,0;1671679, topByrGms=12345.67, usrCurncy=1, vbsTopByrGmb=167167.67}
So I thought al.getValue
will be a Map
and I can iterate it like this- 所以我认为
al.getValue
将是一个Map
,我可以像这样迭代它-
for (Map.Entry<Integer, Integer> entry : al.getValue().entrySet()) {
System.out.println("Key = " + entry.getKey() + ", Value = " + entry.getValue());
}
But it is giving me compilation error at entrySet()
with red color. 但这在红色的
entrySet()
处给了我编译错误。 And I am not sure how can I iterate over the value
as clearly while inspection, I can see that as LinkedHashMap<K,V>
. 而且我不确定在检查时如何清楚地迭代该
value
,可以看到它为LinkedHashMap<K,V>
。
Can anyone help me with this? 谁能帮我这个?
You need to do a cast . 你需要做一个演员 。 The compiler does not know that
al.getValue()
is of type Map<Integer, Integer>
, so you have to tell him specifically: 编译器不知道
al.getValue()
的类型为Map<Integer, Integer>
,因此您必须专门告诉他:
for (Map.Entry<Integer, Integer> entry : ((Map<Integer, Integer>) al.getValue()).entrySet()) {
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